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Vikki [24]
3 years ago
6

What is the solution to the system of equations?

Mathematics
1 answer:
motikmotik3 years ago
4 0

Answer:

a. it has no solution

b. you can only substitute by making either the 'x' or 'y' the subject of either of the two equations.

Step-by-step explanation:

3x - 9y = -13.............. eqn 1

x - 3y = -7................... eqn 2

from eqn 2

x - 3y = -7, substitute by making 'x' the subject

x = -7 + 3y.................. eqn 3

put eqn 3 into eqn 1

3x - 9y = -13

3( -7 + 3y) - 9y = -13

-21 + 9y - 9y = -13

9y - 9y = -13 + 21

0 = 8, which is not possible.

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Im almost done with this and i need help
jarptica [38.1K]
You need help with the whole thing?
3 0
3 years ago
Can anyone help me?
ArbitrLikvidat [17]

Answer:

The factored form of 4<em>m</em>³ – 28<em>m</em>² – 120<em>m</em> is 4<em>m</em>(<em>m</em> – 10)(<em>m</em> + 3). The zeroes of the function would be <em>m</em> = 0, <em>m</em> = –3, and <em>m</em> = 10.

Step-by-step explanation:

I'll give this a shot.

4<em>m</em>³ – 28<em>m</em>² – 120<em>m</em> = 0 — The original expression

4<em>m</em>³ – 28<em>m</em>² – 120<em>m</em> — Did that 0 have any purpose? I just deleted it.

4(<em>m</em>³ – 7<em>m</em>² – 30<em>m</em>) — There's a common factor in here, 4. Let's pull that aside.

4m(<em>m²</em> – 7<em>m</em> – 30) — Actually, there's <em>two</em> common factors. The second one is <em>m</em>! Let's pull <em>that</em> out too!

To factor an expression, you have to break apart the middle term, so to speak. That's only possible if you can find two numbers whose product equals that of the outside terms and whose sum equals the middle term. Here, I'm just dealing with numbers and putting that variable aside.

–30 = 10 × –3

–30 = –10 × 3

–30 = –2 × 15

–30 = 2 × –15 — To solve for any potential factors, let's find all the numbers integers that multiply to –30

Now let's see which one adds up to –7!

15 – 2 = 13 — it's not this one

2 – 15 = –13 — nor this one

10 – 3 = 7 — we're pretty close! Let's switch that negative

3 – 10 = –7 — here we go! Here's our numbers!

4<em>m</em>[(<em>m</em>² – 10<em>m</em>) + (3<em>m</em> – 30)] — now we break apart the middle term. This is <em>all</em> multiplied by 4<em>m</em>, so that still encases everything with brackets.

4<em>m</em>[<em>m</em>(<em>m</em> – 10) + 3(<em>m</em> – 10)] — Factoring the two expressions

4<em>m</em>(<em>m</em> + 3)(<em>m</em> – 10) — simplifying to find our answer! Ta-da!

8 0
3 years ago
PLZ NEED HELP ASAP!!!
madam [21]

Answer:

C and D

Step-by-step explanation:

I had this same problem on my quiz

4 0
3 years ago
I don't know to find the answer to 8. Can someone explain to me?
lapo4ka [179]
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.

A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'

B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)

C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)

D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n

_____
* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.

The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
7 0
3 years ago
After being exposed to an incredible shrinking machine, Halley's height decreased by 108 cm over 6 seco
uysha [10]

Answer:

it would be -18

Step-by-step explanation:

because you would divide 108 by 6 and you will get -18 each second

6 0
3 years ago
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