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amm1812
3 years ago
6

SIMPLIFY the expression! Please!

Mathematics
2 answers:
Levart [38]3 years ago
5 0

1+3^2 = 1+9 = 10

10/5 = 2

2-6+2 = -4+2

 answer is -2

Misha Larkins [42]3 years ago
5 0
Your answer is -2 hope this helps!
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Answer the equations:<br> 1. 4x+16<br> 2. 8 + 4x+8<br> 3. x+8+x<br> 4. 4+2x+4<br> 5. x+1+2x+8
andrew-mc [135]

Answer:

Answers below

Step-by-step explanation:

1)  4 (x+4)

2) 4x + 16

3) 2x+8

4) 2x+8

5) 3x+9

3 0
3 years ago
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Multiplying by which number is equivalent to finding 15%?
Ahat [919]
.15 is your answer, seeing as .15 is equivalent to 15%
3 0
3 years ago
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Estimate 36.76 divided by 2.9 using compatible numbers - will give brainliest for correct answer
vekshin1

Answer:

12.68 if you are rounding to the hundreths place

Step-by-step explanation:

8 0
3 years ago
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Consider the probability that greater than 94 out of 153 people will not get the flu this winter. Assume the probability that a
Hatshy [7]

Answer:

0.8212 = 82.12% probability that greater than 94 out of 153 people will not get the flu this winter.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.65, n = 153. So

\mu = E(X) = 153*0.65 = 99.45

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{153*0.65*0.35} = 5.9

Consider the probability that greater than 94 out of 153 people will not get the flu this winter

This probability is 1 subtracted by the pvalue of Z when X = 94. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{94 - 99.45}{5.9}

Z = -0.92

Z = -0.92 has a pvalue of 0.1788

1 - 0.1788 = 0.8212

0.8212 = 82.12% probability that greater than 94 out of 153 people will not get the flu this winter.

7 0
3 years ago
What is 1 38/40 simplified
sesenic [268]
Your answer will be 1 19/20

hope this helps
5 0
4 years ago
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