500 or 600 depending on the maths question
Answer:
One solution.
Step-by-step explanation:
To determine the number of possible solutions for a triangle with A = 113° , a = 15, and b = 8, we're going to use the law of sines which states that: "<em>When we divide side a by the sine of angle A it is equal to side b divided by the sine of angle B, and also equal to side c divided by the sine of angle C</em>".
Using the law of sines we have:


Solving for B, we have:

∠B = 29.4°
Therefore, the measure of the third angle is: ∠C = 37.6°
There is another angle whose sine is 0.4909 which is 180° - 29.4° = 150.6 degrees. Given that the sum of all three angles of any triangle must be equal to 180 deg, we can't have a triangle with angle B=113° and C=150.6°, because B+C>180.
Therefore, there is one triangle that satisfies the conditions.
Answer:
Answer
Let height =h
Total surface area=2πr(r+h)
r=7cm
⇒968=2×
7
22
×7(7+h)
⇒
44
968
=7+h
⇒h+7=22
⇒h=22−7
=15cm.
Step-by-step explanation:
<h3>
Answer: 9V</h3>
=============================================================
Reason:
The volume expression of a cone with radius r and height h is

Let's plug in the given height h = 12 and we'd get

This is the volume of the first cone. We're told the first cone has a volume of V, so we can say 
We can't find the actual numeric volume because we don't know what value replaces r. So we leave it as is.
The second cone has the same height (h = 12) but the radius is now 3 times in size. Instead of r, we use 3r
Replace every copy of r with 3r. Then simplify

The radius tripled which results in a volume that's 9 times bigger.
Answer:
76 on second exam, 80 on third exam
Step-by-step explanation:
First, find the total of all 3 test scores by multiplying the average by the number of elements. 81 · 3 = 243.
The first score is 83 so 243 - 83 = 160. 160 is the other two test scores combined.
To find the other 2 scores, divide 160 by 2, which is 80.
The second score is 4 less so it will be 76. The third score is 80.