(g o f)(x)=g(f(x))
basically
put f(x) for every x in g(x)
g(f(x))=7(f(x))
f(x)=x+5
g(f(x))=7(x+5)
g(f(x))=7x+35
(g o f)(x)=7x+35
Answer:
10 ft x 10 ft
Area = 100 ft^2
Step-by-step explanation:
Let 'S' be the length of the southern boundary fence and 'W' the length of the eastern and western sides of the fence.
The total area is given by:

The cost function is given by:

Replacing that relationship into the Area function and finding its derivate, we can find the value of 'S' for which the area is maximized when the derivate equals zero:

If S=10 then W =20 -10 = 10
Therefore, the largest area enclosed by the fence is:

12/15 = 8/x
Cross multiply:
12*x = 8*15
⇒ 12*x= 120
⇒ (12/12)*x = 120/12
⇒ x= 10.
Final answer: x=10.
Hope this helps~
Answer:
Disagree, as m is common to all terms of the expression and thus, can be factored. The factored expression is 7m(2 + 3p - 5q)
Step-by-step explanation:
If a variable is common to all terms of an expression, it can be factored.
14m + 21pm - 35mq
Here, m is common to all terms of the expression, so the factored expression is:

Disagree, as m is common to all terms of the expression and thus, can be factored. The factored expression is 7m(2 + 3p - 5q)