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dezoksy [38]
3 years ago
11

Rebecca walks nine dogs each week she gets paid $10 a week +2 for each dog she walks which expression can be used to find how mu

ch is Rebecca gets paid in one week
Mathematics
1 answer:
kaheart [24]3 years ago
3 0

Answer:

F(x)= 2x + 10

Step-by-step explanation:

F(×) represent the total amount she will get that week.

The 2 represents her dog bonus, x how many dogs she walked.

10 is the bare minimum she makes each week and it never changes.

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Solve the following equation:(g x f)(x) when f(x) = x+5 and g(x) = 7x
Lubov Fominskaja [6]
(g o f)(x)=g(f(x))

basically
put f(x) for every x in g(x)
g(f(x))=7(f(x))
f(x)=x+5
g(f(x))=7(x+5)
g(f(x))=7x+35


(g o f)(x)=7x+35
8 0
3 years ago
ANSWER 100 pts PLS <br> Write the following series in sigma notation.<br> 4+6+8+10+12+14
balandron [24]

Answer:

47890

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A farmer wants to fence a rectangular garden next to his house which forms the northern boundary. The fencingfor the southern bo
Ivahew [28]

Answer:

10 ft x 10 ft

Area = 100 ft^2

Step-by-step explanation:

Let 'S' be the length of the southern boundary fence and 'W' the length of the eastern and western sides of the fence.

The total area is given by:

A=S*W

The cost function is given by:

\$ 120 = \$3*2W+\$6*S\\20 = W+S\\W = 20-S

Replacing that relationship into the Area function and finding its derivate, we can find the value of 'S' for which the area is maximized when the derivate equals zero:

A=S*(20-S)\\A=20S-S^2\\\frac{dA}{dS} = \frac{d(20S-S^2)}{dS}\\0= 20-2S\\S=10

If S=10 then W =20 -10 = 10

Therefore, the largest area enclosed by the fence is:

A=S*W\\A=10*10 = 100\ ft^2

5 0
3 years ago
What is the solution to the proportion?
blsea [12.9K]
12/15 = 8/x

Cross multiply:
12*x = 8*15
⇒ 12*x= 120
⇒ (12/12)*x = 120/12
⇒ x= 10.

Final answer: x=10.

Hope this helps~
4 0
3 years ago
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Frankie factored the expression ls 14m + 21pm - 35mq as 7(2m + 3pm - 5mq) . She thinks she has factored out the greatest common
shtirl [24]

Answer:

Disagree, as m is common to all terms of the expression and thus, can be factored. The factored expression is 7m(2 + 3p - 5q)

Step-by-step explanation:

If a variable is common to all terms of an expression, it can be factored.

14m + 21pm - 35mq

Here, m is common to all terms of the expression, so the factored expression is:

7m(\frac{14m}{7m} + \frac{21pm}{7m} - \frac{35mq}{7m}) = 7m(2 + 3p - 5q)

Disagree, as m is common to all terms of the expression and thus, can be factored. The factored expression is 7m(2 + 3p - 5q)

7 0
3 years ago
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