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3 years ago

7

A photocopy of a polygon was reduced to 80% of its original size. The , the copy was again reduced to 80% of its size. What is t

he ratio of the corresponding sides of the second photocopy to the original?

1 answer:

siniylev [52]3 years ago

5 0

I’m pretty sure it is 16/25

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Learn with an example

Marina86 [1]

Answer:

$\large{\textbf{f(g(x)) = 20}\\}$

Step-by-step explanation:

$\large{\textup{Given}:\\$f(x) = 5x $ \hspace{5mm} \& \hspace{5mm} $g(x) = 4x $\\$$ f \circ g(x) = f(g(x)) $$\\$ \implies f(g(x)) = f(5x) $\\\textup{i.e., To substitute $5x$ instead of $x$ in $f(x)$}\\$\implies f(5(x)) = 4(5(x)) = 20x \\ $\textup{Now,}$f(g(1)) = 20(1) =20$}$

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3 years ago

Solve the equation for the variable specified. df + 10h = 3 Solve for d. A. d 3= 10h f B. d. 3- 10h f C. d = 3 - 102 D. d = f(3

Nesterboy [21]

Answer:

Step-by-step explanation:

d= (3-10h)/f

6 0

3 years ago

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tekilochka [14]

$rt=d\qquad\text{divide both sides by}\ r\neq0\\\\\dfrac{rt}{r}=\dfrac{d}{r}\\\\\boxed{t=\dfrac{d}{r}}$

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svet-max [94.6K]

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svetlana [45]

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