Solve the following quadratic. `x^{2}\ +\ 4x\ +\ 1\ =\ 6`

Mathematics

1 answer:

Flauer [41]3 years ago

7 0

Answer:

x = -5 and 1

Step-by-step explanation:

1. Subtract 6 from both sides to get x²+4x-5=0

2. Factor the quadratic equation. Find two numbers that have a sum of 4 and a product of (-5). The numbers 5 and (-1) add to 4 and multiply to get -5

3. The factored equation is (x+5)(x-1)=0

4. Set each factor to equal zero and solve for x.

x+5=0 ... x=-5

x-1=0 ... x=1

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if you want it to be exactly 2, then you have to make sure the equations are proportional.
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Answer:

attached

Step-by-step explanation:

attached

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Nutka1998 [239]

I'm assuming you're looking to find the expanded form of the number?

This number is in scientific notation. The easiest way to convert it to a normal number is to move the decimal place 14 to the right. I've attached a picture showing how to do this. You should get 630,000,000,000,000

There's a faster way to do this - notice that you need to move the decimal 14 to the right, and there's one number already after the decimal place. Therefore, 13 places will be filled with zeros. So, just write out 63 and add 13 zeros.

For more general help on scientific notation, check out these videos: https://www.khanacademy.org/math/pre-algebra/pre-algebra-exponents-radicals/pre-algebra-scientific-notation/v/scientific-notation-old

Hope that helps! Feel free to message me or leave a comment if I can clarify anything :)