Solve the following quadratic.
`x^{2}\ +\ 4x\ +\ 1\ =\ 6`
       
      
                
     
    
    
    
    
    1 answer:
            
              
              
                
                
Answer:
x = -5 and 1
Step-by-step explanation:
1. Subtract 6 from both sides to get x²+4x-5=0
2. Factor the quadratic equation. Find two numbers that have a sum of 4 and a product of (-5). The numbers 5 and (-1) add to 4 and multiply to get -5
3. The factored equation is (x+5)(x-1)=0
4. Set each factor to equal zero and solve for x. 
x+5=0 ... x=-5
x-1=0 ... x=1
 
                                
             
         	    You might be interested in
    
        
        
Answer: we dont have options
Step-by-step explanation:
 
        
             
        
        
        
Answer:
Question 7 = $2
Question 8 = $16
 
        
                    
             
        
        
        
Ans: y = -25x+225 or f(x) = -25x+225
        
             
        
        
        
B. 
9 = 3 x 3
21 = 3 x 7
GCF = 3
3 x 3 + 3 x 7 = 9 + 21 = 30