Solve the following quadratic. `x^{2}\ +\ 4x\ +\ 1\ =\ 6`
1 answer:
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Y+4<u><</u>9
subtract 4
y<u><</u>5
y is smaller than and equal to 5
so you shade from 5 to the negative end to infinity (to the left) and shade the 5 to show that it is included (attachment says A)
6 less than (-6) 2 times a number (2 time x) is greater than (>) 8 (8)
-6+2x>8
add 6
2x>14
divide 2
x>7
so
x is bigger than 7
shade from 7 to the positive end to infinity (to the right) and don't shade 7 but put a circle around it to show that it is not included (attachment says B )
I have included pictures of the number lines
subtract 4
y<u><</u>5
y is smaller than and equal to 5
so you shade from 5 to the negative end to infinity (to the left) and shade the 5 to show that it is included (attachment says A)
6 less than (-6) 2 times a number (2 time x) is greater than (>) 8 (8)
-6+2x>8
add 6
2x>14
divide 2
x>7
so
x is bigger than 7
shade from 7 to the positive end to infinity (to the right) and don't shade 7 but put a circle around it to show that it is not included (attachment says B )
I have included pictures of the number lines
