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Levart [38]
3 years ago
8

Help me please I have no clue

Mathematics
1 answer:
emmainna [20.7K]3 years ago
7 0

Answer:

x = 12.8

Step-by-step explanation:

i use this calculator to find triangle measurements as long as you know like three values it works

https://www.calculator.net/triangle-calculator.html?vc=90&vx=&vy=10&va=38&vz=&vb=&angleunits=d&x=79&y=19

ik sending a link is hecka sus but you can just look up triangle calculator and it'll pop up

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If AC = 10 and CG = 21, find AG.
stellarik [79]
The answers 59 because 90 degrees is the angle so 21 plus 10 equals 31 and 90-31 equals 59
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Can anyone give me the answer and how to do it
Gelneren [198K]

Answer:

54 - 10y

Step-by-step explanation:

Distribute each of the 3 parenthesis

= 12y + 24 - 32y + 32 - 10y - 2 ← collect like terms

= 54 - 10y

7 0
3 years ago
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a backyard has an area of 72 square feet. of the following choices, which is the smallest possible perimeter of the backyard?
mr Goodwill [35]
34 is the smallest possible perimeter
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Tiffany sold 4 paintings in 3.5 months. Which rate represents this situation? A.3.5paintings/4months B.14months/4paintings C.4pa
Masja [62]
Yea  it is C

4  in 3.5 months.
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3 years ago
Use scalar projection to show that the distance from a point P1(x1,y1) to the line ax+by+c=0 is |ax1+by1+c|/underroot(a^2 +b^2)
Elina [12.6K]

Answer:

d = 13 / 5 units          

Step-by-step explanation:

Given:

- Point P = (-2 , 3 )

- line : 3x - 4y + 5 = 0

Find:

- Use projection to show the given formula

- use the formula to find the distance from given point and line.

Solution:

- Let line L be defined as:

                                     a*x + b*y + c = 0

- Choose A as fixed point on the line L whose coordinates are ( m , k ).

- Now the coordinates of any point (x , y ) can be given by the line L:

                                    a*( x - m ) + b*( y - k ) + c = 0

- We did that by subtracting the coordinates (x,y) from (m,k).

- The above line can represented by dot product of constants (a , b ) to vector coordinates between points (x,y) to (m,k):

                                   ( a , b ) . ( x - m , y - k) = 0

- For above expression to be true i.e the dot product of two vectors is only zero when the vectors are orthogonal. So vector (a , b ) is always perpendicular to every vector in direction of line L

- The vector:

                                         v =  ( x - m , y - k)

- It may represent the line connecting the points (x_1 , y_1) and (m, k).

Then the distance d from the point P_1: (x_1, y_1) to the line L is given by the magnitude of the scalar projection of v onto a, because the latter is the length of the side of a right  triangle with two of the vertices being P_1 and

( m , k), and the other vertex lying on L So:

                                      d = | component v along x |

                                      d =  | v . ( a , b ) | / | (a , b ) |

                                      d = | (x_1 - m , y_1 - k ) . ( a , b)| / sqrt(a^2 + b^2)

                                      d = | ax_1 + by_1 - (a*m + b*k) | / sqrt(a^2 + b^2)

Where point A (m,k) lies on line hence;

                                      a*m + b*k + c = 0

                                      c = - (a*m + b*k)

Hence,

                                      d = | ax_1 + by_1 + c | / sqrt(a^2 + b^2)

- Given point P (-2,3) and line L : 3x - 4y + 5 = 0

where,

                                    (x_1 , y_1) = (-2 , 3 )

                                     (a , b) = ( 3 , -4 )

                                            c = 5

-Evaluate:

                                    d = | 3*(-2) + -4*3 + 5 | / sqrt(3^2 + 4^2)

                                    d = | - 13 | / 5

                                    d = 13 / 5 units                                    

                               

6 0
3 years ago
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