The relative unfairness of an apportionment that gives a new board member to joshua rather than to salinas will be
<h3>How to calculate the values?</h3>
The relative unfairness of an apportionment that gives a new board member to joshua rather than to salinas will be:
= (1520 - 1232)/1232
= 288/1232
= 0.234
The relative unfairness of an apportionment that gives a new board member to salinas rather than to Joshua will be:
= (1448 - 1333)/1333
= 115/1333
= 0.086
The regional governing board that should receive the new board member is Salinas.
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Since each girl gets 11 sticker that means that there are 22 stickers in the pack.
11x2=22
He needs to fence the entire perimeter, so all you have to do is find the perimeter. P= S+S+S+S, which is 125, 200, 125, and 200. Add them together and you get 650, so he needs 650 feet of fence.
3. {6,9,15)
for these u have use Pythagoras theorem
Options :
A. The initial number of bacteria is 7.
B. The initial of bacteria decreases at a rate of 93% each day.
C. The number of bacteria increases at a rate of 7% each day.
D. The number of bacteria at the end of one day is 360.
Answer:
C. The number of bacteria increases at a rate of 7% each day.
Step-by-step explanation:
Given the function :
f(x)=360(1.07)^x ; Number of bacteria in sample at the end of x days :
The function above represents an exponential growth function :
With the general form ; Ab^x
Where A = initial amount ;
b = growth rate
x = time
For the function :
A = initial amount of bacteria = 360
b = growth rate = (1 + r) = 1.07
If ; (1 + r) = 1.07 ; we can solve for r to obtain the daily growth rate ;
1 + r = 1.07
r = 1.07 - 1
r = 0.07
r as a percentage ;
0.07 * 100% = 7%
