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BaLLatris [955]
3 years ago
5

Which of the following lines has a zero slope

Mathematics
2 answers:
kirill [66]3 years ago
6 0
Can you show me the lines

malfutka [58]3 years ago
6 0

Answer:

show me the lines

Step-by-step explanation:

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5. Let f(x) = 3x3/4 and g(x) = -2x314 Find (f + g)(x). Please show work.​
pishuonlain [190]

Answer:

I don't have a clue

Step-by-step explanation:

3 0
3 years ago
(Will give Brainliest/5 Stars if correct answer)
tensa zangetsu [6.8K]
Answer: Choice D) 
The angle between the two vectors is approximately 71.6 degrees

----------------------------------------------
----------------------------------------------

Work Shown: 

Each time I write the word "dot" I mean "dot product". 

|u| = length of vector u
|u| = sqrt(u dot u)
|u| = sqrt(<8,4> dot <8,4>)
|u| = sqrt(8*8 + 4*4)
|u| = sqrt(64 + 16)
|u| = sqrt(80)
|u| = sqrt(16*5)
|u| = sqrt(16)*sqrt(5)
|u| = 4*sqrt(5)

-----------------------

|v| = length of vector v
|v| = sqrt(v dot v)
|v| = sqrt(<9,-9> dot <9,-9>)
|v| = sqrt(9*9 + (-9)*(-9))
|v| = sqrt(81+81)
|v| = sqrt(2*81)
|v| = sqrt(2)*sqrt(81)
|v| = sqrt(2)*9
|v| = 9*sqrt(2)

-----------------------

u dot v = <8,4> dot <9,-9>
u dot v = 8*9 + 4*(-9)
u dot v = 72-36
u dot v = 36

-----------------------

cos(theta) = (u dot v)/(|u|*|v|)
cos(theta) = (36)/(4*sqrt(5)*9*sqrt(2))
cos(theta) = (36)/(36*sqrt(10))
cos(theta) = 1/(sqrt(10))
cos(theta) = sqrt(10)/10
theta = arccos(sqrt(10)/10)
theta = 71.56505
which rounds to 71.6 when rounding to one decimal place (nearest tenth)

That's why the approximate answer is roughly 71.6 degrees

7 0
3 years ago
(Help, please! I'll give the branliest to whoever figures it out first!)
Burka [1]
C. 1, all the other answers are negative
6 0
3 years ago
Read 2 more answers
Can u help me with this :p
Ne4ueva [31]

Answer:

12.5

10

Step-by-step explanation:

10(1/2+3/4)

5+7.5

12.5

10(1/2)+(8(3/4)-1)

5+(6-1)

5+5

10

4 0
3 years ago
Determine which of the following are equivalence relations and/or partial ordering relations for the given sets: A = { lines in
VLD [36.1K]

Answer:

Check the explanation

Step-by-step explanation:

1

a) A is an Equivalence Relation

Reflexive : x is parallel to itself => x R x

Symmetric : x is parallel to y => y is parallel to x.

Therefore x R y => y R x

Transitive :  x is parallel to y and y is parallel to z then x, y, z are parallel to each other.

=> x R y and y R z => x R z

Therefore A is equivalent.

1. b)

x r y if and only if |x-y| less than or equal to 7

Reflexive : |x-x| = 0 <= 7 => x R x Satisfied.

Symmetric : let x R y => |x-y| <= 7

Consider |y-x| = |(-1)*(x-y)| = |x-y| <= 7

=> y R x => Satisfied

Transitive : let x R y and y R x

=> |x-y| <= 7 and |y-z| <= 7

but this doesn't imply x R z

Counter-Example : x = 1, y = 7, z = 10

Therefore this relation is neither Equivalent nor Partial Order Relation.

8 0
4 years ago
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