With amounts measured in gallons, let
x = amount of 65% antifreeze
y = amount of 90% antifreeze
1 gal of the 65% brand contains 0.65 gal of pure antifreeze; x gal would contain 0.65x gal. Similarly, y gal of the 90% brand contains 0.90y gal of pure antifreeze.
To obtain 120 gal of 80% antifreeze solution (which contains 0.80•120 = 96 gal of pure antifreeze), we must have
x + y = 120 … … … … … [total volume of antifreeze solution]
0.65x + 0.90y = 96 … [total volume of pure antifreeze]
Solve the first equation for y :
y = 120 - x
Substitute this into the second equation and solve for x :
0.65x + 0.90 (120 - x) = 96
0.65x + 108 - 0.90x = 96
0.25x = 12
x = 48
Solve for y :
y = 120 - 48
y = 72
Answer:
The answer of the question is 5
There is no solution since ln(0) is undefined
Answer: "
-2y³ + 3y²<span>
+ 27y " .
_______________________________________________________Refer to the completed chart below (image attached).</span>
_______________________________________________________Using the completed chart below (image attached), we can write out the terms:
__________________________________________________ y³ − 3y³ + 9y² + 3y² − 9y² + 27y ;
Then, we can combine the "like terms" ;
__________________________________________y³ − 3y³ = -2y³ ;
+9y² + 3y² − 9y² = + 3y² ;
___________________________________________________________to get: -2y³ + 3y² ; and bring down the "+27y" ;
___________________________________________________________ Answer: "
-2y³ + 3y²<span>
+ 27y " . </span>Refer to chart below (image attached).
___________________________________________________________
Answer:
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