All categories

3 years ago

Someone pls help me!! thank you!!

Mathematics

1 answer:

romanna [79]3 years ago

6 0

Final Answer is 4.5

= 4.5hours more time was used on games than on research.

You might be interested in

Lindsay has scored 15 goals in 10 lacrosse games this season. a) What is her unit rate of scoring? b) How many goals might Linds

pashok25 [27]

A)1.5 goals per match
b) 1.5x35= 52.5 so 53
Assuming she is consistent

8 0

3 years ago

Rational number between 5.2 and 5.5

Zinaida [17]

5.3

or

5.4

or

5.48

Any of these is a rational number between 5.2 and 5.5.

8 0

3 years ago

Read 2 more answers

Heeeeelp Find the distance of AB if A (2, 6) and B (-5, 2).

evablogger [386]

Answer:

let A (2, 6) be (x1, y1)

B (-5, 2) be (x2, y2)

distance AB =√[(x2 - x1)² + (y2 - y1)²]

√[(-7)²+ (-4)²]

√65

7 0

4 years ago

Multiply. (3.5x10^-5) (3x10^-10) express your answer in scientific notation.

Len [333]

Answer:

5.69034 × 1011

Step-by-step explanation:

Decimal

1234000000

Scientific Notation

1.234 x 10^9

×10^

1st Number

1.234

×10^

Operation

2nd Number

5.678

×10^

3 0

3 years ago

When studying radioactive material, a nuclear engineer found that over 365 days, 1,000,000 radioactive atoms decayed to 973 co

HACTEHA [7]

Answer:

A. number of decayed atoms = 73.197

Step-by-step explanation:

In order to find the answer we need to use the radioactive decay equation:

$N(t)=N0*e^{kt}$ where:

N0=initial radioactive atoms

t=time

k=radioactive decay constant

In our case, when t=0 we have 1,000,000 atoms, so:

$1,000,000=N0*e^{k*0}$

$1,000,000=N0$

Now we need to find 'k'. Using the provied information that after 365 days we have 973,635 radioactive atoms, we have:

$973,635=1,000,000*e^{k*365}$

$ln(973,635/1,000,000)/365=k$

$-0.0000732=k$

A. atoms decayed in a day:

$N(t)=1,000,000*e^{-0.0000732t}$

$N(1)=1,000,000*e^{-0.0000732*1}$

$N(1)= 999,926.803$

Number of atoms decayed in a day = 1,000,000 - 999,926.803 = 73.197

B. Because 'k' represents the probability of decay, then the probability that on a given day 51 radioactive atoms decayed is k=0.0000732.

4 0

3 years ago