Answer:
The team can assign field positions to 9 of the 19 players in 181,440 different ways.
Step-by-step explanation:
Since the outfielders (left field, center field, right field) can play any outfield position, the infielders (1st base, 2nd base, 3rd base, short stop) can play any infield position, the pitchers can only pitch, and the catchers can only catch, supposing a certain team has 20 players, of whom 3 are catchers, 4 are outfielders, 6 are infielders, and 7 are pitchers, to determine how many ways can the team assign field positions to 9 of the 19 players, putting each of the 9 selected players in a position he can play, and ensuring that all 9 field positions are filled, the following calculation must be performed:
3 x 7 x 6 x 5 x 4 x 3 x 4 x 3 x 2 = X
21 x 30 x 12 x 24 = X
630 x 12 x 24 = X
181,440 = X
Therefore, the team can assign field positions to 9 of the 19 players in 181,440 different ways.
Answer:
3y= -42
y= -14
Step-by-step explanation:
3y= -42
-42/3= -14
y= -14
The random probability of event X, wheel stopping on a white slice is 0.9 while the probability of not X, wheel stopping on Grey slice is 0.1
- Total numbers on wheel = total possible outcomes = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
- Grey colored portion = {3}
- White colored portion = {1, 2, 4, 5, 6, 7, 8, 9, 10}
- X = Event that wheel stops on a white slice
- P(X) = number of white slices ÷ total number of slices
Therefore, the probability that wheel stops on a white slice is 0.9 while, the probability that wheel does not stop on a white slice is 0.1
Learn more :brainly.com/question/18153040
Well perimeter is lengthx2 and widthx2 so 7x2=14
then 64-14=50
50÷2= 25
length=25
11% not 100% sure Bc I calculated but hope it helped!
