Matthew practiced playing the guitar for 2/3 hours. Natalie practiced playing the guitar 1 3/4 times as long as

A television with a 5:3 screen shows an image with a ratio of 5:4 which creates a letter boxed image. What percent of the screen

lions [1.4K]

Answer:

C

Step-by-step explanation:

8 0

3 years ago

Can you guys help again

dangina [55]

Answer:

Step-by-step explanation:

1 = 27

2 = 36

2 = 1,000

3 0

3 years ago

Read 2 more answers

Solve the equation below for x. -1 2(3x - 4) = 11

Lesechka [4]

Answer:

x= 37/36

Step-by-step explanation:

−12(3x−4)=11

Step 1: Simplify both sides of the equation.

−12(3x−4)=11

(−12)(3x)+(−12)(−4)=11(Distribute)

−36x+48=11

Step 2: Subtract 48 from both sides.

−36x+48−48=11−48

−36x=−37

Step 3: Divide both sides by -36.

−36x

−36

=

−37

−36

x=

37

36

Answer:

x=

37

36

8 0

3 years ago

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A box with a hinged lid is to be made out of a rectangular piece of cardboard that measures 3 centimeters by 5 centimeters. Six

kherson [118]

Answer:

x = 0.53 cm

Maximum volume = 1.75 cm³

Step-by-step explanation:

Refer to the attached diagram:

The volume of the box is given by

$V = Length \times Width \times Height \\\\$

Let x denote the length of the sides of the square as shown in the diagram.

The width of the shaded region is given by

$Width = 3 - 2x \\\\$

The length of the shaded region is given by

$Length = \frac{1}{2} (5 - 3x) \\\\$

So, the volume of the box becomes,

$V = \frac{1}{2} (5 - 3x) \times (3 - 2x) \times x \\\\V = \frac{1}{2} (5 - 3x) \times (3x - 2x^2) \\\\V = \frac{1}{2} (15x -10x^2 -9 x^2 + 6 x^3) \\\\V = \frac{1}{2} (6x^3 -19x^2 + 15x) \\\\$

In order to maximize the volume enclosed by the box, take the derivative of volume and set it to zero.

$\frac{dV}{dx} = 0 \\\\\frac{dV}{dx} = \frac{d}{dx} ( \frac{1}{2} (6x^3 -19x^2 + 15x)) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\0 = \frac{1}{2} (18x^2 -38x + 15) \\\\18x^2 -38x + 15 = 0 \\\\$

We are left with a quadratic equation.

We may solve the quadratic equation using quadratic formula.

The quadratic formula is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Where

$a = 18 \\\\b = -38 \\\\c = 15 \\\\$

$x=\frac{-(-38)\pm\sqrt{(-38)^2-4(18)(15)}}{2(18)} \\\\x=\frac{38\pm\sqrt{(1444- 1080}}{36} \\\\x=\frac{38\pm\sqrt{(364}}{36} \\\\x=\frac{38\pm 19.078}{36} \\\\x=\frac{38 + 19.078}{36} \: or \: x=\frac{38 - 19.078}{36}\\\\x= 1.59 \: or \: x = 0.53 \\\\$