The amount of time saved on the 86.0 mile trip from Tulsa entrance to Oklahoma City is 0.42 hours
<h3>What is time?</h3>
Time is the measurement of a past, present, or future event. The S.I unit of time is seconds (s)
To get the time that was saved on the 8.6-mile trip, we use the formula below.
Formula:
- Ts = (d/v₁)-(d/v₂)................. Equation 1.
Where:
- Ts = Time saved on the trip
- d = distance covered during the trip
- v₁ = Initial legal speed limit
- v₂ = final/current legal speed limit.
From the question,
Given:
- d = 86.0 mile
- v₁ = 55.0 mi/h
- v₂ = 75.0 mi/h
Substitute these values into equation 1
- Ts = (86/55)-(86/75)
- Ts = 1.564-1.147
- Ts = 0.42 h.
Hence, The amount of time saved on the 86.0 mile trip from Tulsa entrance to Oklahoma City is 0.42 hours.
Learn more about time here: brainly.com/question/13893070
Answer:
I think the 1st statement is right.
Explanation:
Wind patterns doesn't stay the same.
Waves don't follow the same patterns.
Waves move further up the shore.
I didn't hear about "waves adding" before..so i guess 1st statement is right.
The image of the black body curve is missing, so i have attached it.
Answer:
T ≈ 3372 K
Explanation:
From the attached curve of the black star, if we trace the peak value of the wavelength from the graph, we will see that it is approximately 859.5 nm.
Thus; λ_peak = 859.5 × 10^(-9) m
From wiens law, we know that;
T•λ_peak = 2.898 × 10^(-3) m.K
Where T is surface temperature.
Plugging in the relevant values, we can find the temperature T
Thus;
T = (2.898 × 10^(-3))/(859.5 × 10^(-9))
T ≈ 3372 K
Just do energy spent divided by time to get your answer. With this we can say a human might be able to!
Answer:
the time it will take the element to decay to 1.9 g is 34.8 mins.
Explanation:
Given;
half life of Nitrogen, t = 10 min
initial mass of the element, N₀ = 20 g
final mass of the element, N = 1.9 g
The time taken for the element to decay to final mass is calculated as follows;
time (min) mass remaining
0 ----------------------------------20 g
10 mins ------------------------- 10 g
20 mins ------------------------- 5 g
30 mins -------------------------- 2.5 g
40 mins --------------------------- 1.25 g
Interpolate between 2.5 g and 1.25 to obtain the time for 1.9 g
30 min ------------------------- 2.5 g
x ----------------------------------- 1.9 g
40 min -------------------------- 1.25 g

Therefore, the time it will take the element to decay to 1.9 g is 34.8 mins.