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Natasha_Volkova [10]
3 years ago
13

When a wave crosses from one medium to another where the wave speed is slower. The frequency of the wave is unchanged. The wavel

ength: a) increases b) decreases c) stays the same d) No answer text provided.
Physics
2 answers:
barxatty [35]3 years ago
8 0

Answer:

a. Its wavelength decreases

Explanation:

This is because from refractive index, n = v₁/v₂ = fλ₁/fλ₂ where v₁,v₂ and λ₁,λ₂ are the wave speeds in medium 1 and 2 and wavelengths in medium 1 and 2 respectively and f is the frequency of the wave.

If v₂ is the slower speed, it follows that

v₂ = v₁/n

fλ₂ = fλ₁/n   (since f is constant)

λ₂ = λ₁/n

Since the wavelength λ₁ is reduced by a factor n, λ₂ thus decreases.

So the wavelength decreases in the slower medium

pantera1 [17]3 years ago
7 0

Answer:

A).Increase

Explanation:

Refraction is the change in direction of waves that occurs when waves travel from one medium to another. Refraction is always accompanied by a wavelength and speed change. Diffraction is the bending of waves around obstacles and openings. The amount of diffraction increases with increasing wavelength.

Frequency doesn't change because it depends on travelling of waves across the interface. But speed and wavelength change as the material on the other side may be different, so now it might have a longer/shorter size of wave and so the number of waves per unit time changes.

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True or false? When an object deforms, the change of shape is always permanent.<br> false<br> true
Alik [6]
True. Because say if you go to a junk place where you can break anything and you decide to squish a printer with a car and when you go look at the printer it’s all deformed there’s really no way that you can fix it. Lol that was an example
8 0
3 years ago
Una persona de 80kg intenta bajar de peso subiendo una montaña para quemar el equilante a una rebanada de pastel de chocolate (7
SCORPION-xisa [38]

Answer:

Explanation:

An 80kg person tries to lose weight by climbing a mountain to burn the equivalent of a large slice of a rich chocolate cake (700kcl). How high should you climb?

Given that,

A person of mass

M = 80kg

The person is climbing a stair case and he burn an energy of 700 kcl

We know that 1kcl = 4184J

Then, 700kcl = 700 × 4184J

700kcl = 2.9288 × 10^6 J

We want to find height of stairs the person will climb when he Loss 700kcl. The energy he burns will be converted to the potential energy

P.E is calculated using

P.E = mgh

Where

m is mass in kg

g is gravitational constant g = 9.81m/s2

h is the height of stairs he climb in metre

Then,

P.E = energy burn

mgh = 700kcl

80 × 9.81 × h = 2.9288 × 10^6

h = (2.9288 × 10^6) / (80 × 9.81)

h = 3731.91m

So, the person will climb 3731.91m before he losses 700kcl

In espanyol

Dado que,

Una persona de masa

M = 80 kg

La persona está subiendo una escalera y quema una energía de 700 kcl.

Sabemos que 1kcl = 4184J

Entonces, 700kcl = 700 × 4184J

700kcl = 2.9288 × 10 ^ 6 J

Queremos encontrar la altura de las escaleras que la persona subirá cuando pierda 700kcl. La energía que quema se convertirá en energía potencial.

P.E se calcula utilizando

P.E = mgh

Dónde

m es masa en kg

g es constante gravitacional g = 9.81m / s2

h es la altura de las escaleras que sube en metros

Entonces,

P.E = quema de energía

mgh = 700kcl

80 × 9.81 × h = 2.9288 × 10 ^ 6

h = (2.9288 × 10 ^ 6) / (80 × 9.81)

h = 3731.91m

Entonces, la persona subirá 3731.91m antes de perder 700kcl

5 0
3 years ago
What is an inertial reference frame?
Gennadij [26K]
<h2>Answer: A system in which Newton's Laws are fulfilled</h2>

An inertial reference system is a reference system in which the principle of inertia is fulfilled, which is one of Newton's laws:

<em>"For a body to have acceleration, an external force must act on it" </em>

In addition, the other Newton's laws of movement are fulfilled.

Therefore, the variation of the linear momentum of the system is equal to the actual forces on the system.

8 0
3 years ago
One object (LaTeX: m_1m1) has a mass of 2 kg and moves with a speed of 9 m/s to the right. Another object (LaTeX: m_2m2) has a m
defon

Answer:

The correct answer is B

Explanation:

The moment of an object is the product of its mass by velocity, it is described by the equation

          p = mv

In this problem they give us the most body and speeds before and after the crash. We must define an environment with both bodies so that the forces during the crash have been internalized and the moment is preserved

         Δp = pf -p₀

         Δp = m v_{f} - m v₀

         Δp = 2 9 -2 1.5

         ΔP = 14.8 m/s

The correct answer is b

7 0
3 years ago
(I) A car slows down from 28 m????s to rest in a distance of 88 m. What was its acceleration, assumed constant?
Nataly [62]

Answer:

The  value is  a = -  4.45 m/s^2

Explanation:

From the question we are told that  

       The  initial speed is  u  =  28 \  m/s at a distance of  s_1  =  0 \ m

        The  final speed is  v  =  0 \  m/s    at a distance of  s_2 =  88 \  m

Generally  from the  kinematic equation we have that

       v^2  =  u^2  +2as

=>   a = \frac{v^2  -  u^2  }{ 2(s_2  -  s_1 )}

=>  a = \frac{0 -  28^2  }{ 2(88  -  0 )}

=>   a = -  4.45 m/s^2

The negative sign shows that it is decelerating

6 0
4 years ago
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