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Complete Question </u></h3>
Q)Two loudspeakers, A and B, are driven by the same amplifier as shown and emit sinusoidal waves in phase. Speaker B is 2.00 m to the right of speaker A. Consider point Q along the extension of the line connecting the speakers, 1.00 m to the right of speaker B. Both speakers emit sound waves that travel directly from the speaker to point Q. a) What is the lowest frequency for which constructive interference occurs at point Q? b) What is the lowest frequency for which destructive interference occurs at point Q? The speed of sound wave is 344 m/s.
Answer:
lowest frequency is 172 Hz. for n = 1
lowest frequency is 86 Hz for n = 0
Explanation:
(a) Constructive interference takes place when the path difference is n where n=1,2,3 ...
frequency f = v /λn
= v n / d
= n ( 344 / 2 )
= n ( 172 ) Hz.
lowest frequency is 172 Hz
b)Destructive interference takes place when the path difference is n/2 x where n=1,3,5 ...
λ = 4/2n+1
for n = 0
λ = 4m
f = 344/4
f = 86 Hz.
lowest frequency is 86 Hz
Answer:
I don't know I'm sorry I will tell you another answer asks me
Answer: Acceleration
Detailed Explanation:
Acceleration is defined as the rate of change of velocity.
The problem describes the relationship of "bulb a" and "bulb b" to be in connected in series. When the switch is open then no current can flow, on the other hand, when it is closed, current will pass through.
When only "bulb a" is connected to the battery then more current is flowing to "bulb a" causing it to be bright.
Closing the switch would mean that "bulb b" is already included in the circuit and the battery will push small current to flow around the whole circuit. The more bulbs are connected, the harder for the current to flow because the resistance will be very high.
So the light of "bulb a" will be dimmer.
To solve this problem it is necessary to apply the concepts related to Faraday's law and the induced emf.
By definition the induced electromotive force is defined as
Where,
Electric field
B = Magnetic Field
A = Area
At the theory the magnetic field is defined as,
Where,
N = Number of loops
I = current
Permeability constant
We know also that the cross sectional area, is the area from a circle, and the length is equal to the perimeter then
A = \pi r^2
l = 2\pi r
Replacing at the previous equation we have that
Where,
R = Radius of the solenoid
r = The distance from the axis
Re-arrange to find the current in function of time,
Replacing our values we have
