Question

How much work does this force do as the particle moves along the x-axis from x = 0 to x = l? express your answer in terms of the variables f0 and l?

Answer 1

Answer;

= F0 L ( 1 - 1/e )

Explanation;

Work done is given as the product of force and distance.

In this case;

Work done  = ∫︎ F(x) dx  

                    = F0 ∫︎ e^(-x/L) dx  

                    = F0 [ -L e^(-x/L) ] between 0 and L  

                    = F0 L ( 1 - 1/e )