How much work does this force do as the particle moves along the x-axis from x = 0 to x = l? express your answer in terms of the
1 answer:
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Answer:
g = 11.2 m/s²
Explanation:
First, we will calculate the time period of the pendulum:
where,
T = Time period = ?
t = time taken = 135 s
n = no. of swings in given time = 98
Therefore,
T = 1.38 s
Now, we utilize the second formula for the time period of the simple pendulum, given as follows:
where,
l = length of pendulum = 54 cm = 0.54 m
g = acceleration due to gravity on the planet = ?
Therefore,
<u>g = 11.2 m/s²</u>
Kinetic energy and potential energy pair is the quantity in which one will increase then other will decrease
As we know that sum of kinetic energy and potential energy will always remain conserved
So here we will have
so here as we move away from mean position the kinetic energy will decrease while at the same time potential energy will increase.
So the pair of potential energy and kinetic energy will satisfy the above condition
Answer:
0.0018 W/m²
Explanation:
Power and intensity are related as:
P= 20.0 W (given)
r = 30.0 m (given)
Intensity in decibels: