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2 years ago

What is the sum? I really need help ASAP

Mathematics

1 answer:

olya-2409 [2.1K]2 years ago

5 0

Answer:

im confussed

Step-by-step explanation:

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Which statement is NOT true? A. All isosceles triangles are also equilateral triangles. B. All equilateral triangles are also is

Alecsey [184]

Hello there!

The statement that would NOT be true would be option A. All isosceles triangles are also equilateral triangles. The rest of the statements would be TRUE.

Hope this helps and have a great day! :)

5 0

3 years ago

Consider a game in which a participant pays $2 to roll a die. The participant receives $3 if they roll a 1 (i.E. They go up by a

Sauron [17]

Answer:

The expected monetary value of a single roll is $1.17.

Step-by-step explanation:

The sample space of rolling a die is:

S = {1, 2, 3, 4, 5 and 6}

The probability of rolling any of the six numbers is same, i.e.

P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = $\frac{1}{6}$

The expected pay for rolling the numbers are as follows:

E (X = 1) = $3

E (X = 2) = $0

E (X = 3) = $0

E (X = 4) = $0

E (X = 5) = $0

E (X = 6) = $4

The expected value of an experiment is:

$E(X)=\sum x\cdot P(X=x)$

Compute the expected monetary value of a single roll as follows:

$E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17$

Thus, the expected monetary value of a single roll is $1.17.

7 0

3 years ago

If P(x) = 0.40, find the complement

Maksim231197 [3]

The answer would be .50.

3 0

3 years ago

What is the volume of this cylinder? Use 3.14 and round your answer to the nearest hundredth. the diameter is 16 cm and the heig

Zanzabum

Find the area of the base $A=64\pi$ .

Multiply area of the base by height to get volume

$V=20\cdot64\pi=4021.24$

Hope this helps.

5 0

2 years ago

Read 2 more answers

Logb(x-1) + logb(x+2) = logb(8-2x)

Aleksandr [31]

Answer:

x=2

Step-by-step explanation:

log_x(y)+log_x(z)=log_x(yz), so logb(x-1) + logb(x+2)=logb((x-1)(x+2)). next subtract logb(8-2x) from both sides to get logb((x-1)(x+2))-logb(8-2x)=0. log_x(y) - log_x(z) = log_x(y/z). so now we have logb((x-1)(x+2)/(8-2x)). now you can put it into exponential form: (x-1)(x+2)/(8-2x)=b^0=1 now just solve for x:

(x-1)(x+2)= 8-2x, x^2 + x -2 = 8-2x, x^2 + 3x -10 = 0, (x+5)(x-2)=0 x=-5, x=2. plug both into the original equation to check which one is correct, since log_x(y) can't have a negative y, x=-5 doesnt work

7 0

2 years ago