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2 years ago

What is the sum? I really need help ASAP

Mathematics

1 answer:

olya-2409 [2.1K]2 years ago

5 0

Answer:

im confussed

Step-by-step explanation:

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Find the volume of a pyramid with a square base, where the perimeter of the base is 10.7\text{ ft}10.7 ft and the height of the

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Answer:

$V=23.37\ ft^3$

Step-by-step explanation:

Given that,

The perimeter of the base of pyramid, P = 10.7 ft

The height of the pyramid, h = 9.8 ft

We need to find the volume of the pyramid.

The perimeter of square is given by :

4s = 10.7, s is side

s = 2.675 ft

Now the volume of pyramid is given by :

$V=\dfrac{lbh}{3}\\\\=\dfrac{2.675^2\times 9.8}{3}\\\\V=23.37\ ft^3$

So, the volume of the pyramid is equal to $23.37\ ft^3$ .

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A teenager who is 5 feet tall throws an object into the air. The quadratic function LaTeX: f\left(x\right)=-16x^2+64x+5f ( x ) =

tia_tia [17]

Answer:

At approximately x = 0.08 and x = 3.92.

Step-by-step explanation:

The height of the ball is modeled by the function:

$f(x)=-16x^2+64x+5$

Where f(x) is the height after x seconds.

We want to determine the time(s) when the ball is 10 feet in the air.

Therefore, we will set the function equal to 10 and solve for x:

$10=-16x^2+64x+5$

Subtracting 10 from both sides:

$-16x^2+64x-5=0$

For simplicity, divide both sides by -1:

$16x^2-64x+5=0$

We will use the quadratic formula. In this case a = 16, b = -64, and c = 5. Therefore:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Substitute:

$\displaystyle x=\frac{-(-64)\pm\sqrt{(-64)^2-4(16)(5)}}{2(16)}$

Evaluate:

$\displaystyle x=\frac{64\pm\sqrt{3776}}{32}$

Simplify the square root:

$\sqrt{3776}=\sqrt{64\cdot 59}=8\sqrt{59}$

Therefore:

$\displaystyle x=\frac{64\pm8\sqrt{59}}{32}$

Simplify:

$\displaystyle x=\frac{8\pm\sqrt{59}}{4}$

Approximate:

$\displaystyle x=\frac{8+\sqrt{59}}{4}\approx 3.92\text{ and } x=\frac{8-\sqrt{59}}{4}\approx0.08$

Therefore, the ball will reach a height of 10 feet at approximately x = 0.08 and x = 3.92.

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2 years ago