1.
If no changes are made, the school has a revenue of :
625*400$/student=250,000$
2.
Assume that the school decides to reduce n*20$.
This means that there will be an increase of 50n students.
Thus there are 625 + 50n students, each paying 400-20n dollars.
The revenue is:
(625 + 50n)*(400-20n)=12.5(50+n)*20(20-n)=250(n+50)(20-n)
3.
check the options that we have,
a fee of $380 means that n=1, thus
250(n+50)(20-n)=250(1+50)(20-1)=242,250 ($)
a fee of $320 means that n=4, thus
250(n+50)(20-n)=250(4+50)(20-4)=216,000 ($)
the other options cannot be considered since neither 400-275, nor 400-325 are multiples of 20.
Conclusion, neither of the possible choices should be applied, since they will reduce the revenue.
Answer:
2.50$
Step-by-step explanation:
4 / 8 = 0.5
0.5 x 5 = 2.5
Making a list can help you solve a problem by:
•making more organized
•it can make it easier to organize data
•helps you stay on track
those are some of the basic ways,
Answer:
-4
Step-by-step explanation:
In the Whisker-Box plot, the Lower Quartile can be found by the end of the left side of the box. In this case, it is directly above the -4, and so is your answer.
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*See attached picture.
