Answer:
Probability that at least 490 do not result in birth defects = 0.1076
Step-by-step explanation:
Given - The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC). A local hospital randomly selects five births and lets the random variable X count the number not resulting in a defect. Assume the births are independent.
To find - If 500 births were observed rather than only 5, what is the approximate probability that at least 490 do not result in birth defects
Proof -
Given that,
P(birth that result in a birth defect) = 1/33
P(birth that not result in a birth defect) = 1 - 1/33 = 32/33
Now,
Given that, n = 500
X = Number of birth that does not result in birth defects
Now,
P(X ≥ 490) =
= + .......+
= 0.04541 + ......+0.0000002079
= 0.1076
⇒Probability that at least 490 do not result in birth defects = 0.1076
Answer:
x = 5 (please read the step by step explanation)
Step-by-step explanation:
So, I'm just going to solve for x because the instructions aren't too clear. I believe there is supposed to be an image attached to it, but seeing as I don't have that, I'll just solve for x and you can plug in with the values.
15x = 12x + 15
Same to both sides:
3x = 15
Isolate x:
x = 5
Just plug in those values and you'll be good to go! Have a good day!
Answer:
36
Step-by-step explanation:
you have to isolate your variable. To do this, you add 24 to each side. On the left side its 12+24 and on the right, its 24+(-24) which then equals zero. In simple terms, x=12+24