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Arlecino [84]
3 years ago
11

My dog weighs less than 70 pounds. Write the inequality for the possible weights of my dog.

Mathematics
1 answer:
Sladkaya [172]3 years ago
3 0
An inequality could be X<70
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Answer:

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Step-by-step explanation:

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2 years ago
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What is the measure of CED?
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Answer:

try 106, if its not try 108

Step-by-step explanation:

6 0
3 years ago
Jane is the regional manager of Graphic DesignWorks. She uses a company
Lelechka [254]
The answer is D. $3200
4 0
3 years ago
Tyler ate x fruit snacks, and Han ate 3/4 less that. write an expression for the number of fruit snacks Han ate​
Alika [10]

x = ×-3/4

because you hace the variable x and you do not know the number of fruit snacks he ate and you need to have the same variables to properly find the answer.

3 0
3 years ago
The circumference of a sphere was measured to be 82 cm with a possible error of 0.5 cm.
Nat2105 [25]

Answer:

A) Maximum error = 170.32 cm³

B)Relative error = 0.0575

Step-by-step explanation:

A) Formula for circumference is: C = 2πr

Differentiating with respect to r, we have;

dC/dr = 2π

r is small, so we can write;

ΔC/Δr = 2π

So, Δr = ΔC/2π

We are told that ΔC = 0.5.

Thus; Δr = 0.5/2π = 0.25/π

Now, formula for Volume of a sphere is;

V(r) = (4/3)πr³

Differentiating with respect to r, we have;

dV/dr = 4πr²

Again, r is small, so we can write;

ΔS/Δr = 4πr²

ΔV = 4πr² × Δr

Rewriting, we have;

ΔV = ((2πr)²/π) × Δr

Since C = 2πr, we now have;

ΔV = (C²/π)Δr

ΔV will be maximum when Δr is maximum

Thus, ΔV = (C²/π) × 0.25/π

C = 82 cm

Thus;

ΔV = (82²/π) × 0.25/π

ΔV = 170.32 cm³

B) Formula for relative error = ΔV/V

Relative error = 170.32/((4/3)πr³)

Relative error = 170.32/((4/3)C³/8π³)

Relative errror = 170.32/((4/3)82³/8π³)

Relative error = 170.32/2963.744

Relative error = 0.0575

3 0
3 years ago
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