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Iteru [2.4K]
2 years ago
10

plz help me i dont want the answer i just wanna know how to do it if i fail this test i fail my grade plz hep

Mathematics
2 answers:
svp [43]2 years ago
8 0

Answer:

The answer is 7

Step-by-step explanation:

We know that the velocity can be calculated from the equation of the distance traveled divided by time

Then

s =  \frac{d}{t }  \\ s =  \frac{ \frac{1}{8} }{ \frac{1}{56} }  =  \frac{56}{8}  = 7

I am a math teacher. If you need any explanation you can communicate with me from whats in this number 01557831028.

hoa [83]2 years ago
5 0
I’m pretty sure his speed is 1 mile per hour. hope this helps you!
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Pls solve this with step by step.
MAVERICK [17]

Step-by-step explanation:

-x+5+6x-7x-14

6x-8x+5-14

-2x-9

3 0
1 year ago
What do they represent?
andrey2020 [161]

Answer:

A

Step-by-step explanation:

If you convert the first equation to y=mx+b form, it will be the same as the second equation.

6x - 15y = 15

-15y = -6x + 15

y = \frac{2}{5}x -1

Because the 2 equations are the same now, they are the same line.

8 0
3 years ago
The value of y varies directly with x and y=3 when x=-6. Find y when x=1
Iteru [2.4K]
Hi, ok all you need to do is use the direct variation formula which is= y/x=y/x so you will replace your numbers by each value which get us to = 3/-6=y/1 so you cross multiply which gives us 3=-6y you divide 3 by -6 and that is the value of y, thank you for reading hope it helps ;)
6 0
3 years ago
Show that x = -2 is a solution of 3x² + 13x + 14 = 0​
Oliga [24]

Answer:

x= -2 is correct answer

Step-by-step explanation:

3(-2×-2)+13(-2)+14=0

3(4)+13(-2)+14=0

12+(-26)+14=0

12-26+14=0

12+14-26=0

26-26=0

0=0

3 0
3 years ago
The simplified expression
Romashka-Z-Leto [24]

Answer:

5x^2 y^2

Step-by-step explanation:

We need to use the properties shown below to solve this:

1. \sqrt[n]{x^a} =x^{\frac{a}{n}}

2. \sqrt{x}\sqrt{x}  =x

3.  \sqrt{x} \sqrt{y}=\sqrt{x*y}

Area of a triangle is given by  1/2 * base * height, so we do that and simplify:

A=\frac{1}{2}(\sqrt{5x^3} )(2\sqrt{5xy^4} )\\A=\frac{1}{2}(5x^3)^{\frac{1}{2}}*2*(5xy^4)^{\frac{1}{2}}\\A=\sqrt{5}x^{\frac{3}{2}}*\sqrt{5}\sqrt{x} }  y^2\\A=\sqrt{5} \sqrt{5}x^{\frac{3}{2}} x^{\frac{1}{2}}y^2\\A=5*x^2y^2\\A=5x^2 y^2

6 0
3 years ago
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