Question

Simplify the complex numbers and arrange them in increasing order of their absolute value (modulus).

Answer 1

Answer:

The  complex numbers arranged  in increasing order of their absolute value (modulus) are:      

1. -5(n³-n²-1)+ n(n²-n)  
2. (n²-1)(n +2)  -n² (n-3)
3. 2n( n²-2n-1) + 3n²
4. n² (n-4) + 5n³ -6  

Step-by-step explanation:

-5(n³-n²-1)+ n(n²-n)

= -5n³+5n²+5+  n³-n²   (multiplying)

= -6n³+6n²+5

(n²-1)(n +2)  -n² (n-3)

= n³+2n²-n -2 - n³+ 3n²          (multiplying)

=5n²-n -2

n² (n-4) + 5n³ -6

= n³- 4n +5n³ -6                  (multiplying)

= 6n³- 4n  -6

2n( n²-2n-1) + 3n²

= 2n³- 4n²  -2n + 3n²

=2n³ +n²  -2n

First we solve the expression by multiplying adding or subtracting . Then we take the expression whose answer is the highest both in co efficient and the power to be the last  in number as we have to write the expression in increasing order , mso we will start with the smallest.

The expression whose answer is the smallest both in co efficient and the power  is taken to be thefirst in number as we have to write the expression in  increasing order. The negative co efficients and less powers are taken to be the smallest in value.