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Kaylis [27]
3 years ago
8

HELP ASAP On this math

Mathematics
2 answers:
S_A_V [24]3 years ago
8 0

Answer:

x = 2, y = 14

x = 3, y = 10

x = 4, y = 6

x = 5, y = 2

Step-by-step explanation:

y = 22 - 4x

When x = 2,

y = 22 - 4(2)

=> y = 22 - 8

=> y = 14

When x = 3,

y = 22 - 4(3)

=> y = 22 - 12

=> y = 10

When x = 4,

y = 22 - 4(4)

=> y = 22 - 16

=> y = 6

When x = 5,

y = 22 - 4(5)

=> y = 22 - 20

=> y = 2

Naya [18.7K]3 years ago
3 0
1. y = 14 because you plug in 2 for x. (22 - 4 * 2)
2. y = 10 because you plug in 3 for x. (22 - 4 * 3)
3. y = 6 because you plug in 4 for x. (22 - 4 * 4)
4. y = 2 because you plug in 5 for x. (22 - 4 * 5)

Hopefully this was helpful!
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What two numbers multiply to negative 54 and add up to 3
DENIUS [597]
The roots of 54 are: 1 and 54, 2 and 27, 3 and 18, 6 and 9, then it restarts all over again.

The two numbers have to multiply up to 54, and add up to 3. 9 and 6 have a difference of 3, and the multiplied sum is negative, so this is your pair.

9 and -6 fit this criteria, since they add up to 3 and multiply to 64.
6 0
3 years ago
Read 2 more answers
What is 9/1 times 7/10
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To multiply two fractions:

-- Multiply their numerators; the product is the numerator of the new fraction.

9 x 7 = 63 ; the new fraction is (63) / (something)

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3 years ago
the jurassic zoo charged $11 for each adult admission and $8 for each child. the total bill for the 195 people from a school tri
Otrada [13]

Children : 144

Adults : 51

Explanation

Step 1

Set the equations

let

x represents the number of children

y represents the number of adults

charge per child:8

charge per adult:11

total people:195

then

a)the total people is 195, so

x+y=195\rightarrow equation(1)

b) the total bill was $1713,so

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but,

total adults cost= rate*number of adults

total children cost= rate*number of childe

replacing

8x+11y=1713\rightarrow equation(2)

Step 2

solve the equations,

\begin{gathered} x+y=195\rightarrow equation(1) \\ 8x+11y=1713\rightarrow equation(2) \end{gathered}

a) isolate the x value from equation 81) and replace in eqaution (2)

\begin{gathered} x+y=195\rightarrow equation(1) \\ \text{subtract y in both sides} \\ x+y-y=195-y \\ x=195-y \end{gathered}

replace in equation (2)

\begin{gathered} 8x+11y=1713\rightarrow equation(2) \\ 8(195-y)+11y=1713 \\ 1560-8y+11y=1713 \\ 3y+1560=1713 \\ \text{subtract 1560 in both sides} \\ 3y+1560-1560=1713-1560 \\ 3y=153 \\ \text{divide bothsides by 3} \\ \frac{3y}{3}=\frac{153}{3} \\ y=51 \end{gathered}

therefore, the number of adults is 51

b) now, replace the y value into equation (1) to find x

\begin{gathered} x+y=195\rightarrow equation(1) \\ x+51=195 \\ \text{subtract 51 in both sides} \\ x+51-51=195-51 \\ x=144 \end{gathered}

so, the number of children is 144

I hope this helps you

4 0
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How do u make x the subject in m=n+x/p
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