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Luba_88 [7]
2 years ago
8

Help me pleasee 20 points ! If u can’t see zoom it please help

Mathematics
1 answer:
Taya2010 [7]2 years ago
3 0

Answer:

1 hr = $60.20

2 hrs. = $120.40

3 hrs. = $180.40

4 hrs. = $240.80

5 hrs. = $301.00

Step-by-step explanation:

Multiply 60.20 by the number of hours to get your answers.

Ex: $60.20 (amount every hour) x 2 (number of hours) = $120.40

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How many times greater is the value of the 3 in 3,499 than in 6,399
boyakko [2]

Answer:

967 times

Step-by-step explanation:

3 / 3499 is 1166.33333

3 / 6399 is 2133

7 0
3 years ago
A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a
zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}

Hence the answer is 0.1157

(ii) None is defective becomes

\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}

hence the answer is 0.4823

(iii) All are defective

\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}

(iv) At least one is defective

This is 1 - probability that none is defective

\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}

Hence the answer is 0.5177

3 0
1 year ago
A proportional function passes though the point (6,2). what is the slope of the line?
Georgia [21]

Answer: (3,1)

Step-by-step explanation: You put y over x and then you simplify it like a fraction and put it back in the form of a coordinate point

6 0
3 years ago
Find the length of the side marked x​
ruslelena [56]

it's a right angled triangle so we will use hypotenuse formula to get the value of x

hypotenuse formula = a² + b² = c²

a = side of the triangle

b = base of traingle

c = hypotenuse ( can be written as h too)

and the formula can also be written as.

c² = a² + b²

<em><u>therefore</u></em><em><u>,</u></em><em><u> </u></em><em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>1</u></em><em><u>2</u></em><em><u>.</u></em><em><u>1</u></em>

<em><u>hope </u></em><em><u>this </u></em><em><u>answer </u></em><em><u>helps</u></em><em><u> </u></em><em><u>you </u></em><em><u>dear.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>take </u></em><em><u>care!</u></em>

3 0
2 years ago
If I have 7 button down shirts, 5 pairs of pants and 3 pairs of shoes that I can wear to work then how many different outfits ca
34kurt

105 different outfits can wear on an individual day

<em><u>Solution:</u></em>

I have 7 button down shirts, 5 pairs of pants and 3 pairs of shoes that I can wear to work

To find: Number of different outfits can I wear on an individual day

First he has to decide on a pair of pants and he has 5 different choices

For each of those choices he has a choice of 7 different button down shirts, so that gives him 5 x 7 = 35 different pant/shirt combinations

For each of those 35 different pant/shirt combinations, he has 3 pairs of shoes he could select, so altogether he has 35 x 3 = 105 different outfits

In short we can say,

different outfits = 7 x 5 x 3 = 105

So there 105 different outfits can wear on an individual day

4 0
3 years ago
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