Answer:
967 times
Step-by-step explanation:
3 / 3499 is 1166.33333
3 / 6399 is 2133
SOLUTION
This is a binomial probability. For i, we will apply the Binomial probability formula
i. Exactly 2 are defective
Using the formula, we have

Note that I made the probability of being defective as the probability of success = p
and probability of none defective as probability of failure = q
Exactly 2 are defective becomes the binomial probability

Hence the answer is 0.1157
(ii) None is defective becomes

hence the answer is 0.4823
(iii) All are defective

(iv) At least one is defective
This is 1 - probability that none is defective

Hence the answer is 0.5177
Answer: (3,1)
Step-by-step explanation: You put y over x and then you simplify it like a fraction and put it back in the form of a coordinate point
it's a right angled triangle so we will use hypotenuse formula to get the value of x
hypotenuse formula = a² + b² = c²
a = side of the triangle
b = base of traingle
c = hypotenuse ( can be written as h too)
and the formula can also be written as.
c² = a² + b²
<em><u>therefore</u></em><em><u>,</u></em><em><u> </u></em><em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>1</u></em><em><u>2</u></em><em><u>.</u></em><em><u>1</u></em>
<em><u>hope </u></em><em><u>this </u></em><em><u>answer </u></em><em><u>helps</u></em><em><u> </u></em><em><u>you </u></em><em><u>dear.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>take </u></em><em><u>care!</u></em>
105 different outfits can wear on an individual day
<em><u>Solution:</u></em>
I have 7 button down shirts, 5 pairs of pants and 3 pairs of shoes that I can wear to work
To find: Number of different outfits can I wear on an individual day
First he has to decide on a pair of pants and he has 5 different choices
For each of those choices he has a choice of 7 different button down shirts, so that gives him 5 x 7 = 35 different pant/shirt combinations
For each of those 35 different pant/shirt combinations, he has 3 pairs of shoes he could select, so altogether he has 35 x 3 = 105 different outfits
In short we can say,
different outfits = 7 x 5 x 3 = 105
So there 105 different outfits can wear on an individual day