I'd say the answer is 5 wins
hope this helps
Step-by-step explanation:
37 and 1/2 divided by 3/16 =
75/2 divided by 3/16 =
75/2 * 16/3 =
25*8 = 200 <--- 75 cancels 3; 16 cancels 2
The answer to this problem “12 = 15(z-1/5) is : Z = 1
Its a right angled triangle. You have C and have B all you need to find is A. usually for a question like this you would use the Pythagorean theorem which is A2+B2=C2 but since we already have c we will use C2-B2=A2
Now we fill in the values. (21)2-(9)2=A2
441-81=360^2 so now with the 360^2 we have to squareroot it so the square root of 360 is 18.973f
now, let's keep in mind that, the integers are consecutrive, therefore, if one is say 2, the other is either, 3 or 1, because 1,2,3 <--- notice, 1 is before 2 and 3 is after 2.
so say, our first integer is "a", then the next one can just be "a+1".
![\bf \begin{cases} a&=small\\ a+1&=\stackrel{consecutive}{large}\\ \end{cases}\qquad \begin{cases} \stackrel{\textit{4 times the small}}{4a}\\ \stackrel{\textit{13 greater than that}}{4a + 13} \end{cases}~\hfill \stackrel{\textit{large}}{a+1}=\stackrel{\stackrel{\textit{13 more than }}{\textit{4 times the small}}}{4a+13} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%20a%26%3Dsmall%5C%5C%20a%2B1%26%3D%5Cstackrel%7Bconsecutive%7D%7Blarge%7D%5C%5C%20%5Cend%7Bcases%7D%5Cqquad%20%5Cbegin%7Bcases%7D%20%5Cstackrel%7B%5Ctextit%7B4%20times%20the%20small%7D%7D%7B4a%7D%5C%5C%20%5Cstackrel%7B%5Ctextit%7B13%20greater%20than%20that%7D%7D%7B4a%20%2B%2013%7D%20%5Cend%7Bcases%7D~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Blarge%7D%7D%7Ba%2B1%7D%3D%5Cstackrel%7B%5Cstackrel%7B%5Ctextit%7B13%20more%20than%20%7D%7D%7B%5Ctextit%7B4%20times%20the%20small%7D%7D%7D%7B4a%2B13%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)

let's recall that, on the negative side in a number line, the closer to 0, the larger the number, therefore, -1,000,000 is a much <u>smaller</u> number than -1, because -1 is closer to 0, thus is larger.