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lina2011 [118]
3 years ago
7

Help with math homework

Mathematics
1 answer:
igomit [66]3 years ago
8 0
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We played 15 games. We have two times as many losses as wins. How many wins do we have?
Hunter-Best [27]
I'd say the answer is 5 wins
hope this helps
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Tom has a can of paint that covers 37 1/2 m² each board on the fence has a area of 3/16 m² how many boards can he paint.
kramer

Step-by-step explanation:

37 and 1/2 divided by 3/16 =

75/2 divided by 3/16 =

75/2 * 16/3 =

25*8 = 200 <--- 75 cancels 3; 16 cancels 2

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3 years ago
Solve for :<br> 12 = 15 (z - 1/5)
Ronch [10]
The answer to this problem “12 = 15(z-1/5) is : Z = 1
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3 years ago
A slide is 21 feet long. To get to the top of the slide, you use a vertical 9-foot high rung ladder. What is the distance, b, fr
mojhsa [17]
Its a right angled triangle. You have C and have B all you need to find is A. usually for a question like this you would use the Pythagorean theorem which is A2+B2=C2 but since we already have c we will use C2-B2=A2
Now we fill in the values. (21)2-(9)2=A2
441-81=360^2 so now with the 360^2 we have to squareroot it so the square root of 360 is 18.973f 
3 0
3 years ago
The larger of two consecutive integers is 13 greater than four times the smaller. Find the integers
Mamont248 [21]

now, let's keep in mind that, the integers are consecutrive, therefore, if one is say 2, the other is either, 3 or 1, because 1,2,3  <--- notice, 1 is before 2 and 3 is after 2.

so say, our first integer is "a", then the next one can just be "a+1".

\bf \begin{cases} a&=small\\ a+1&=\stackrel{consecutive}{large}\\ \end{cases}\qquad \begin{cases} \stackrel{\textit{4 times the small}}{4a}\\ \stackrel{\textit{13 greater than that}}{4a + 13} \end{cases}~\hfill \stackrel{\textit{large}}{a+1}=\stackrel{\stackrel{\textit{13 more than }}{\textit{4 times the small}}}{4a+13} \\\\[-0.35em] ~\dotfill

\bf a+1=4a+13\implies 1=3a+13\implies -12=3a\implies \cfrac{-12}{3}=a \\\\\\ \blacktriangleright -4=a \blacktriangleleft\qquad \qquad \stackrel{\textit{consecutive and large}~\hfill }{a+1\implies -4+1\implies \blacktriangleright -3 \blacktriangleleft}~\hfill \boxed{\stackrel{\textit{small}}{-4}~~,~~\stackrel{\textit{large}}{-3}}

let's recall that, on the negative side in a number line, the closer to 0, the larger the number, therefore, -1,000,000 is a much <u>smaller</u> number than -1, because -1 is closer to 0, thus is larger.

7 0
3 years ago
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