Answer:
Step-by-step explanation: We have to add how much time it took him to do all of his homework. To do this, we have to add 2/3 and 3/5.
First, we have to find a LCM between 3 and 5.
The LCM between those numbers are 15.
Next we find out what number to multiply 3 by to get 15, we multiply it by 5.
2 * 5 = 10
3 * 5 = 15
Next we find out what number to multiply 5 by to get 15, we multiply it by 3.
3 * 3 = 9
5 * 3 = 15
10/15+9/15=19/15
We are left off with 1 4/15
So it took him 1 hour and 4/15 minutes to do his homework.
Answer:
59%
Step-by-step explanation:
all work shown and pictured
Answer:
the answer is A because if it is raised to the power greater than one and is added it will be greater than1
<span>a2 – b2 = (a + b)(a – b) or (a – b)(a + b).
This is the 'Difference of Squares' formula we can use to factor the expression.
In order to use the </span><span>'Difference of Squares' formula to factor a binomial, the binomial must contain two perfect squares that are separated by a subtraction symbol.
</span><span>x^2 - 4 fits this, because x^2 and 4 are both perfect squares, and they are separated by a subtraction symbol.
All you do here to factor, is take the square root of each term.
√x^2 = x
√4 = 2
Now that we have our square roots, x and 2, we substitute these numbers into the form (a + b)(a - b).
</span>
<span>(a + b)(a - b)
(x + 2)(x - 2)
Our answer is final </span><span>(x + 2)(x - 2), which can also be written as (x - 2)(x + 2), it doesn't make a difference which order you put it in.
Anyway, Hope this helps!!
Let me know if you need help understanding anything and I'll try to explain as best I can.</span>
To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band

[recall



or 20(x+5) if you wish.