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Dafna1 [17]
3 years ago
11

What device is often used to locate primer and gunpowder particles by their characteristic size and shape?

Chemistry
1 answer:
Kamila [148]3 years ago
6 0
A chemical test used<span> to develop patterns of </span>gunpowder<span> residues around bullet holes ... -the inner surface of the barrel of a gun leaves </span>its<span> markings on a bullet ... pin will be impressed into the relatively soft metal or the </span>primer<span> on the cartridge case ... such as the </span>size<span> and the </span>shape<span> of the tool (rarely individual </span>characteristics)...
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Excess Ca(OH)2 is shaken with water to produce a saturated solution. The solution is filtered, and a 50.00 mL sample titrated wi
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<u>Answer:</u> The K_{sp} for calcium hydroxide is 5.324\times 10^{-6}

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ca(OH)_2

We are given:

n_1=1\\M_1=0.0983M\\V_1=11.22mL\\n_2=2\\M_2=?M\\V_2=50mL

Putting values in above equation, we get:

1\times 0.0983\times 11.22=2\times M_2\times 50\\\\M_2=0.011M

The concentration of Ca(OH)_2 comes out to be 0.011 M.

The balanced equilibrium reaction for the ionization of calcium hydroxide follows:

Ca(OH)_2\rightleftharpoons Ca^{2+}+2OH^-

The expression for solubility constant for this reaction follows:

K_{sp}=[Ca^{2+}][OH^-]^2

Putting the values in above equation, we get:

K_{sp}=(0.011)\times (2\times 0.11)^2

K_{sp}=5.324\times 10^{-6}

Hence, the K_{sp} for calcium hydroxide is 5.324\times 10^{-6}

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