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victus00 [196]
4 years ago
6

I really need the answer

Chemistry
1 answer:
Aleksandr-060686 [28]4 years ago
7 0
Same, I cannot answer the question. Try asking a high school student
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Both active solar heating systems and passive solar heating systems
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A. reduce the need to use fossil fuels
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What is the basic (smallest) unit of matter
seropon [69]

Answer:

atom

Explanation:

7 0
3 years ago
Manganese metal can be obtained by the reaction of manganese dioxide with aluminium. 4Al(s) + 3MnOz(s) → 2 Al2O3(s) + 3 Mn(s) Ca
Snezhnost [94]

Answer : The enthalpy change of reaction is -1800 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given final reaction is,

4Al(s)+3MnO_2(s)\rightarrow 2Al_2O_3(s)+3Mn(s)    \Delta H=?

The intermediate balanced chemical reaction will be,

(1) 2Al(s)+\frac{3}{2}O_2(g)\rightarrow Al_2O_3(s)    \Delta H_1=-1680kJ/mole

(2) Mn(s)+O_2(g)\rightarrow MnO_2(s)    \Delta H_2=-520kJ/mole

First we will multiply reaction 1  by 2 and reverse reaction of reaction 2 by 3 then adding both the equation, we get :

The expression for final enthalpy is,

\Delta H=[n\times \Delta H_1]+[n\times (-\Delta H_2)]

where,

n = number of moles

\Delta H=[2mole\times (-1680kJ/mole)]+[3\times -(-520kJ/mole)]

\Delta H=-1800kJ

Therefore, the enthalpy change of reaction is -1800 kJ

8 0
3 years ago
Is the answer less dense?
xxMikexx [17]
I believe it is less dense.. that is why ice floats on water
5 0
4 years ago
What amount of SeC16 is needed to produce 4.45 mol of chlorine gas in the
AlladinOne [14]

Answer:

1.48 moles of SeCl6 are needed

Explanation:

Based on the reaction:

SeCl6 + O2 → SeO2 + 3Cl2

<em>1 mole of SeCl6 reacts producing 3 moles of Cl2.</em>

To solve this question we need to use the conversion factor:

1mol SeCl6 = 3mol Cl2

As we want to produce 4.45 moles of Cl2, we need:

4.45 mol Cl2 * (1mol SeCl6 / 3mol Cl2) =

<h3>1.48 moles of SeCl6 are needed</h3>
6 0
3 years ago
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