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Nastasia [14]
3 years ago
10

The process of cellular respiration, which converts simple sugars such as glucose into CO2 and water, is an example of _____. Se

e Concept 8.1 (Page 144) View Available Hint(s) The process of cellular respiration, which converts simple sugars such as glucose into CO2 and water, is an example of _____. See Concept 8.1 (Page 144) a pathway in which the entropy of the system decreases a catabolic pathway an endergonic pathway a pathway that occurs in animal cells but not plant cells a pathway that converts organic matter into energy
Chemistry
1 answer:
Paha777 [63]3 years ago
7 0

a catabolic pathway. Cellular respiration is a catabolic pathway.  

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A sample of oxygen gas was collected via water displacement. since the oxygen was collected via water displacement, the sample i
mylen [45]

The sample of oxygen gas was collected through water displacement. So, the gas collected will be a mixture of oxygen and water vapor.

Given that the total pressure of the mixture of gases containing oxygen and water vapor = 749 Torr

Vapor pressure of pure water at 26.4^{0}C=25.81mmHg

                               = 25.81 mmHg*\frac{1 Torr}{1 mmHg} =25.81 Torr

According to Dalton's law of partial pressures,

Total pressure = Partial pressure of Oxygen gas + Partial pressure of water

  749 Torr = Partial pressure of Oxygen gas + 25.81 Torr

Partial pressure of Oxygen gas = 749 Torr - 25.81 Torr =  723.19 Torr

Therefore the partial pressure of Oxygen gas in the mixture collected will be 723.19 Torr


6 0
3 years ago
Cesium-137 is part of the nuclear waste produced by uranium-235 fission. The half-life of cesium-137 is 30.2 years. How much tim
Aleonysh [2.5K]

Answer:

la primera va con la última

5 0
3 years ago
What do you think is meant by the term pseudoscience?
WITCHER [35]

Answer:

The term "pseudo-science" assumes a criterion that allows a differentiation between science and nonscience, good science and bad science, true and false. ... They must try to understand them and not put out in television programmes the sort of pseudo-science that does not exist in reality

Explanation:

5 0
3 years ago
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Consider the following reaction where Kc = 154 at 298 K.2NO(g) + Br2(g) 2NOBr(g)A reaction mixture was found to contain 4.64×10-
IgorLugansk [536]

Answer:

The reaction is not at equilibrium and reaction must run in forward direction.

Explanation:

At the given interval, concentration of NO = \frac{4.64\times 10^{-2}}{1}M=4.64\times 10^{-2}M

Concentration of Br_{2} = \frac{4.56\times 10^{-2}}{1}M=4.56\times 10^{-2}M

Concentration of NOBr = \frac{0.102}{1}M=0.102M

Reaction quotient,Q_{c} , for this reaction = \frac{[NOBr]^{2}}{[NO]^{2}[Br_{2}]}

species inside third bracket represents concentrations at the given interval.

So, Q_{c}=\frac{(0.102)^{2}}{(4.64\times 10^{-2})^{2}\times (4.56\times 10^{-2})}=106

So, the reaction is not at equilibrium.

As Q_{c}< K_{c} therefore reaction must run in forward direction to increase Q_{c} and make it equal to K_{c}.

4 0
3 years ago
Which radioisotopes have the same decay mode and have half-lives greater than
AveGali [126]

The correct answer is (3)


I-131 and P-32


The explanation:


according to attached table:


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- and the half life of I-131 is 8.021 d (more than one hour)


and They both have β- decay mode and with half-lives greater than hour.


4 0
3 years ago
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