Answers:
1st: 189.6 g/mol
2nd: 0.1357 L
3rd: 1.41 M
Explanation:
Finding Molar Mass:
SnCl2 = <u>Tin(II) Chloride</u>
Tin has a molar mass of <u>118.71 g/mol</u>
Chloride has a molar mass of <u>35.453 g/mol</u>
Chloride*2 = <u>70.906</u>
<u>118.71 + 70.906 ≈ 189.6 g/mol</u>
Finding Liters of Solution:
L = mL/1000
135.7 mL / 1000 = <u>0.1357</u>
Finding Molarity:
molarity = <u>moles of solute / liters of solution</u>
M = (36.4g / 189.6g) / 0.1357 L = <u>1.41 M</u>
Hope this helped ;)
Answer: A.nitrogen,oxygen,and argon
Explanation:
<u>Answer:</u> The mass of iron (III) nitrate is 11.16 g/mol
<u>Explanation:</u>
To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

We are given:
Molarity of solution = 0.3556 M
Molar mass of Iron (III) nitrate = 241.86 g/mol
Volume of solution = 129.8 mL
Putting values in above equation, we get:

Hence, the mass of iron (III) nitrate is 11.16 g/mol
Basic radicals (cations) have been divided into groups based on Ksp values