Answer:
Distribute the 3
Step-by-step explanation:
order of operations mate
The given equation is
We need to solve the equation for q.
<u>Value of q:</u>
The value of q can be determined by solving the equation
for q.
Thus, subtracting both sides of the equation by r, we get;
![a-r=qb](https://tex.z-dn.net/?f=a-r%3Dqb)
Now, dividing both sides of the equation by b, we have;
![\frac{a-r}{b}=\frac{qb}{b}](https://tex.z-dn.net/?f=%5Cfrac%7Ba-r%7D%7Bb%7D%3D%5Cfrac%7Bqb%7D%7Bb%7D)
Simplifying the terms, we get;
![\frac{a-r}{b}=q](https://tex.z-dn.net/?f=%5Cfrac%7Ba-r%7D%7Bb%7D%3Dq)
Therefore, the value of q is ![q=\frac{a-r}{b}](https://tex.z-dn.net/?f=q%3D%5Cfrac%7Ba-r%7D%7Bb%7D)
Hence, Option B is the correct answer.
Answer:
i think it would be adding like terms
Step-by-step explanation:
i only say this because the first step you would do is (4x-7) because of the () but you cant because they arent like terms.....
but just try adding the like terms, but im not completely sure if thats what you do (thats the best i got )
The equivalent expression of
is ![\frac{2x - 1}{2x}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%20-%201%7D%7B2x%7D)
<h3>How to determine the
equivalent expression?</h3>
The expression is given as:
1 minus StartFraction 1 Over x EndFraction divided by 2
Rewrite properly as:
![1 - \frac{1}{x} \div 2](https://tex.z-dn.net/?f=1%20-%20%5Cfrac%7B1%7D%7Bx%7D%20%5Cdiv%202)
Express the division as product
![1 - \frac{1}{x} \times \frac 12](https://tex.z-dn.net/?f=1%20-%20%5Cfrac%7B1%7D%7Bx%7D%20%5Ctimes%20%5Cfrac%2012)
Evaluate the product
![1 - \frac{1}{2x}](https://tex.z-dn.net/?f=1%20-%20%5Cfrac%7B1%7D%7B2x%7D)
Take the LCM
![\frac{2x - 1}{2x}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%20-%201%7D%7B2x%7D)
Hence, the equivalent expression of
is ![\frac{2x - 1}{2x}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%20-%201%7D%7B2x%7D)
Read more about equivalent expression at:
brainly.com/question/27911936
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Answer:
wow nice question but sorry can't answer
Step-by-step explanation: