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NARA [144]
2 years ago
9

IM BEGGING ILL GIVE BRAINLEST PLEASEEEEEEE HELP ME Distance and amount of charge are factors that determine which of the

Physics
1 answer:
zzz [600]2 years ago
8 0

Explanation:

Distance and amount of charge are factors that determine which of the

following quantities?

D. All of the above

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What is the frequency of a radio wave with an energy of 3.686 × 10−24 j/photon?answer in units of hz?
Makovka662 [10]

To solve this problem, we have to use the formula:

E = h f

where E is total energy, h is Plancks constant 6.626x10^-34 J s, f is frequency

 

f = E / h

f = 3.686 × 10−24 J / (6.626x10^-34 J s)

<span>f = 5.56 x 10^9 Hz</span>

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3 years ago
Human activities that impact the water cycle
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Answer:

d

Explanation:

A number of human activities can impact on the water cycle: damming rivers for hydroelectricity, using water for farming, deforestation and the burning of fossil fuels.

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2 years ago
A 3kg box has 45J of gravitational potential energy, how high is it off the ground?
frez [133]

Answer:

1.53m

Explanation:

Given parameters:

Mass of box  = 3kg

Gravitational potential energy  = 45J

Unknown

Height of the box  = ?

Solution:

To solve this problem;

 Gravitational potential energy = mgh

m is the mass

g is the acceleration due to gravity

h is the height

            45  = 3 x 9.8 x h

            h  = 1.53m

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2 years ago
A stationary speed gun emits a microwave beam at 2.10x10^10 Hz. It reflects off a car and returns 638 Hz lower. What is the spee
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The answer is 4.55 m/s!

Explanation:

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6 0
2 years ago
a concave lens creates a virtual image at -47.0 cm and a magnification of +1.75. what is the focal length?
Lilit [14]

The focal length of given concave lens will be -26.85 cm

The height of an image to the height of an object is the ratio that is used to determine a lens' magnification. Additionally, it is provided in terms of object and image distance. It is equivalent to the object distance to image distance ratio.

Given  concave lens creates a virtual image at -47.0 cm and a magnification of +1.75.

We have to find focal length

The focal length can be found out by following way:

Magnification = m = +1.75

m = hi/h

hi = -47 cm

1.75 = -47/h

h = -26.85 cm

So the focal length of given concave lens will be -26.85 cm

Learn more about magnification factor here:

brainly.com/question/6947486

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8 0
1 year ago
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