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Rufina [12.5K]
3 years ago
13

A metal conduit will be used as a pathway for wiring through a concrete block. The conduit is a 4 foot long rod with an outer di

ameter of 2.2 inches and an inner diameter of 2 inches. What is the volume of metal in the conduit in cubic centimeters? ...?
Physics
2 answers:
AlekseyPX3 years ago
7 0

Answer:510. 12 cm^3

The volume of a cylindrical conduit, V=\pi (r_2^2-r_1^2) h

where r_1 is the inner radius, r_2 is the outer radius, h is the length.

First of all, we would covert each parameter into centimeters.

length of the conduit, h=4 ft=4\times 30.48 cm=121.92 cm

outer radius, r_1=2.2/2 in =1.1 in= 1.1\times 2.54 cm=2.79 cm

inner radius, r_1=2/2 in =1 in= 2.54 cm

Insert the values in the volume formula,

V=3.14 \times (2.79^2-2.54^2) \times 121.92 cm^3=510. 12 cm^3

Hence, the volume of metal in the conduit is 510. 12 cubic centimeters.

V125BC [204]3 years ago
5 0
We assume this conduit is in a cylindrical form. So that the volume can be calculated by the expression given as:

V=πr²h

However, we the conduit has a hollow space and this should not be included in the volume. We calculate as follows:

V(outer cylinder) = πr²h = π(2.2/2)²(4)(12) = 182.46 in³
V(inner cylinder ) = πr²h = π(2/2)²(4)(12) =  48π in³
V = 182.46 in³ - 48π in³ = 31.66 in³ ---->ANSWER
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A speedboat is approaching a dock at 25 m/s (56 mph). When the dock is 150 m away, the driver begins to slow down. a) What accel
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Answer:

a) -2.038 m/s²

b) 40.33 mph

c) 312.5 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-25^2}{2\times 150}\\\Rightarrow a=-2.083\ m/s^2

Acceleration of the boat is -2.083 m/s² if the boat will stop at 150 m.

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times -1\times 150+25^2}\\\Rightarrow v=18.03\ m/s

Speed of the boat by when it will hit the dock is 18.03 m/s

Converting to mph

1\ mile=1609.34\ m

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18.03\times \frac{3600}{1609.34}=40.33\ mph

Speed of the boat by when it will hit the dock is 40.33 mph

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-25^2}{2\times -1}\\\Rightarrow s=312.5\ m

The distance at which the boat will have to start decelerating is 312.5 m

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In an exothermic reaction, energy of reactants is more than the energy of products.

This means that potential energy of products is less than the potential energy of reactants.

Thus, we can conclude that in the reaction A \rightarrow B + C + heat, the potential energy of the products is less than that of the reactant.

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3 years ago
A force of 50n is applied to an object at an angle of 50 degrees measured relative to the horizontal. Determine the horizontal a
kobusy [5.1K]

Answer:

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We can verify this result using the Pythagorean theorem.

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