The answer would be 19.25
Answer:
Step-by-step explanation:
Solution by substitution method
3x+5y=7
and 4x-y=5
Suppose,
3x+5y=7→(1)
and 4x-y=5→(2)
Taking equation (2), we have
4x-y=5
⇒y=4x-5→(3)
Putting y=4x-5 in equation (1), we get
3x+5y=7
⇒3x+5(4x-5)=7
⇒3x+20x-25=7
⇒23x-25=7
⇒23x=7+25
⇒23x=32
⇒x=32/23
→(4)
Now, Putting x=32/23
in equation (3), we get
y=4x-5
⇒y=4(32/23)-5
⇒y=(128-115)/23
⇒y=13/23
∴y=13/23 and x=32/23
Answer:
-34
Step-by-step explanation:
a + b = -6
x + y + z = -2
We want 8a so multiply the first equation by 8
8( a + b) = -6*8
8a+8b = -48
We also want -7x so multiply the second equation by -7
-7(x + y + z) = -2*-7
-7x-7y-7z = 14
Add the two equations together
8a+8b = -48
-7x-7y-7z = 14
-------------------------
8a+8b-7x-7y-7z = -34
Rearranging the order
8a - 7x - 7z - 7y + 8b = -34
Answer:
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