Answer:
7/25
Step-by-step explanation:
θ lies in quadrant ii
so 2θ lies in quadrant iv
csc θ=5/3
sin θ=3/5 (sin θ=1/csc θ)
[cos(α+β)=cosαcosβ-sinαsinβ]
cos (2θ)=cos(θ+θ)=cos θ cos θ-sin θ sin θ=cos² θ-sin ²θ=1-sin²θ-sin²θ=1-2sin²θ
=1-2 (3/5)²
=1-2(9/25)
=1-18/25
=(25-18)/25
=7/25
-12/6+2
=-12/6+2/1
=-2/1+2/1
=-2+2/1
=0
From looking at that equation you put this is my solution.
Answer:
luh jusko kalisod ba search mo yan sa goohle
Answer:
ABC~WXY by AA
Step-by-step explanation:
In ΔABC
∠B = 90°
∠A = 27°
To Find ∠C
Angle sum property: The sum of all angles of triangle is 180°
∠A+∠B+∠C=180°
27°+90°+∠C=180°
∠C=180°-117°
∠C=63°
In ΔWXY
∠X = 90°
∠Y = 63°
We will use angle sum property
So, ∠W+∠Y+∠X=180°
90°+63°+∠W=180°
∠W=180°-(90°+63°)
∠W=27°
So, ∠A=∠W
∠B =∠X
∠C = ∠Y
So, ABC~WXY by Angle - Angle property.
Hence ABC~WXY by AA
