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sergiy2304 [10]
3 years ago
11

HEY CAN ANYONE PLS ANSWER DIS MATH QUESTION!!

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
5 0

Answer:

y = 2/5x + -5 I think

Step-by-step explanation:

Hope this helps you.

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You work for a manufacturing company and have just completed the budget process for the upcoming business year. At the end of th
fiasKO [112]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
WILL GIVE BRAINLIEST: Which function has a removable discontinuity?
elena55 [62]

Answer:

First choice

Step-by-step explanation:

The discontinuity is removable if by reducing the fraction that discontinuity doesn't continue to exist as a discontinuity.

Example of, (x-1)/(x-1) has a a discontinuity at x=1 and it's removable because the fraction reduces to 1 which doesn't have a discontinuity at x=1.

Example not of, (x-1)/(x-2) has a discontinuity at x=2 and it is not removable because we can't get rid of the x-2 factor in the denominator.

The first choice has a discontinuity at x=-1 and it is removable because x^2-x-2=(x-2)(x+1) and the x+1's will cancel on top and bottom making the point at x=-1 a removable discontinuity.

8 0
3 years ago
Find the missing factor.<br> n(n-3)+2(n-3)=( )(n-3)
elena-s [515]
This is the concept of quadratic equations. We are required to find the missing factor in the partially factored quadratic equation given;
n(n-3)+2(n-3)=()(n-3)
here we proceed as follows;
n(n-3)+2(n-3)
when we factor this we get:
(n-3)(n+2)
this can be written as:
(n+2)(n-3)
The answer is (n+2)
3 0
3 years ago
Integration of sin^2 2x cos^3 2x dx
lilavasa [31]

\int\left[\sin^2(2x)\cos^3(2x)\right]dx=\int\left[\sin^2(2x)\cos^2(2x)\cos(2x)\right]dx\\\\\text{Use the trigonometric identity}\sin^2(x)+\cos^2(x)=1\to\cos^2(x)=1-\sin^2(x)\\\\=\int\left\{\sin^2(2x)[1-\sin^2(2x)]\cos(2x)\right\}dx\\\\\text{substitute}\ \sin2x=t\ \to\ 2\cos2x\ dx=dt\ \to\ \cos2x\ dx=\dfrac{1}{2}\ dt\\\\=\dfrac{1}{2}\int\left[t^2(1-t^2)\right]dt=\dfrac{1}{2}\int(t^2-t^4)dt=\dfrac{1}{2}\left(\dfrac{1}{3}t^3-\dfrac{1}{5}t^5\right)+C


=\dfrac{1}{2}\left(\dfrac{1}{3}\sin^3(2x)-\dfrac{1}{5}\sin^5(2x)\right)+C

4 0
3 years ago
Please I need hep, get free brainly :D
padilas [110]

Step-by-step explanation:

<u>Formula:</u>

\boxed{a = 3.14(r)^{2} }

r represents the radius.

The radius is 1/2 of the diameter.

Since 1/2 of 16 is 8, 8 is our radius.

<u>Substitute:</u>

a = 3.14(8)^{2}

<u>Solve:</u>

a = 3.14(64)

a = 200.96in^{2}

6 0
2 years ago
Read 2 more answers
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