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Misha Larkins [42]
3 years ago
10

In bowling, the distance from the foul line to the headpin is 60 feet. A bowling ball has a radius of about 4.3 Inches. How many

times must a ball rotate in order to strike the head pin
Mathematics
1 answer:
soldi70 [24.7K]3 years ago
4 0

Answer:

  about 26.6 times

Step-by-step explanation:

The circumference of the ball is found from ...

  C = 2πr = 2π(4.3 in) ≈ 27.02 in

There are 12 inches per foot, so the 60 foot distance of interest is ...

  (60 ft)×(12 in/ft) = 120 in

In terms of ball circumference, that distance is ...

  (120 in)/(27.02 in/rotation) ≈ 26.6 rotations

If the ball starts rotating at the foul line, it will turn about 26.6 times before reaching the head pin.

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A real estate company wants to build a parking lot along the side of one of its buildings using 800 feet of fence. If the side a
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Answer:

80,00ft^{2}

Step-by-step explanation:

According to my research, the formula for the Area of a rectangle is the following,

A = L*W

Where

  1. A is the Area
  2. L is the length
  3. W is the width

Since the building wall is acting as one side length of the rectangle. We are left with 1 length and 2 width sides. To maximize the Area of the parking lot we will need to equally divide the 800 ft of fencing between the <u>Length and Width.</u>

800 / 2 = 400ft

So We have 400 ft for the length and 400 ft for the width. Since the width has 2 sides we need to divide 60 by 2.

400/2 = 200 ft

Now we can calculate the maximum Area using the values above.

A = 400ft*200ft

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So the Maximum area we are able to create with 800 ft of fencing is 80,00ft^{2}

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

Read more on Brainly.com - brainly.com/question/12953427#readmore

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