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Misha Larkins [42]
2 years ago
10

In bowling, the distance from the foul line to the headpin is 60 feet. A bowling ball has a radius of about 4.3 Inches. How many

times must a ball rotate in order to strike the head pin
Mathematics
1 answer:
soldi70 [24.7K]2 years ago
4 0

Answer:

  about 26.6 times

Step-by-step explanation:

The circumference of the ball is found from ...

  C = 2πr = 2π(4.3 in) ≈ 27.02 in

There are 12 inches per foot, so the 60 foot distance of interest is ...

  (60 ft)×(12 in/ft) = 120 in

In terms of ball circumference, that distance is ...

  (120 in)/(27.02 in/rotation) ≈ 26.6 rotations

If the ball starts rotating at the foul line, it will turn about 26.6 times before reaching the head pin.

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The solution to the compound inequality given as 3x−8≤23 AND −4x+26≥63 is x ≤ 31/3 AND x ≤ -89/4

<h3>How to determine the solution to the compound inequality?</h3>

The compound inequality is given as:

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Rewrite properly as:

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