1. You con solve the quadratic equation x^2+20x+100=50<span> by following the proccedure below:
2. Pass the number 50 from the right member to the left member. Then you obtain:
x^2+20x+100-50=0
</span><span> x^2+20x+50=0
</span><span>
3. Then, you must apply the quadratic equation, which is:
x=(-b±√(b^2-4ac))/2a
</span><span>x^2+20x+50=0
</span><span>
a=1
b=20
c=50
4. Therefore, when you simplify, the result is:
-10</span><span>±5</span>√2 (It is the last option).<span>
</span>
Answer:
second choice
Step-by-step explanation:
Let x = 5:
Since using x = 5 gives the square root of a negative number, 5 is not in the domain of the composition of the functions.
Answer: second choice
Answer: All real numbers are solutions.
Step-by-step explanation:
<u>Let's solve your equation step-by-step.</u>
−(5x+6)−x=−6−6x
<u>Step 1: Simplify both sides of the equation.</u>
−(5x+6)−x=−6−6x
−5x+−6+−x=−6+−6x(Distribute)
(−5x+−x)+(−6)=−6x−6(Combine Like Terms)
−6x+−6=−6x−6
−6x−6=−6x−6
<u>Step 2: Add 6x to both sides.</u>
−6x−6+6x=−6x−6+6x
−6=−6
<u>Step 3: Add 6 to both sides.</u>
−6+6=−6+6
0=0
Answer:
slope would be zero
Step-by-step explanation:
It is not moving on the graph
Hope this helps!
We can not really tell in this question as you dont know the equation that is being used for the domain and range relationship but overall one should know that:
The set of values of the independent variable(s) for which a function or relation is defined as the domain of a function. Typically, this is the set of x-values that give rise to real y-values.
The range of a function is the complete set of all possible resulting values of the dependent variable (y, usually), after we have substituted the domain.
