Total outcome is 50 [because the number produced by the machine is from 1 to 50]
Question a:
Multiple of 10 are 10, 20, 30, 40, 50
There are five possible outcomes for multiple of 10
P(Multiple of 10) = 5/50 = 1/10
Question b:
Number 1 to 50 will be all the outcomes that are not 100
There are 50 possible outcomes
P(not 100) = 50/50 = 1
Question c:
Multiple of 4 that are less than 50 are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48
There are 12 possible outcomes for multiple of 4
We want 'not multiple of 4' so we need to do 50 - 12 = 38 outcomes
P(not a multiple of 4) = 38/50 = 19/25
Question d:
One digit numbers are 1, 2, 3, 4, 5, 6, 7, 8, 9
There are 9 possible outcomes
P(one-digit number) = 9/50
Answer:
u need to get the y on one side by it self
Step-by-step explanation:
subtract 1/3 y from both sides then subtract x from both sides
Well when it comes to absolute value remember that whatever number is inside the two straight lines will always come out as a positive.
a) [54] would still be 54
b)-[-7 3/5] so first you get the absolute value which comes out to 7 3/5 but because there is a negative sign out side of the two parallel lines, the answer would be -7 3/5
c)[3]-[-1] the absolute value of 3 is 3 and the absolute value of -1 is 1. So the expression would be 3-1 which comes out to 2
d)[2.2-5.13] 2.2-5.13 would equal -2.93 but since it is in the absolute value, the answer would come out as 2.93
Hope this helps!
Answer:
Step-by-step explanation:
<u>Functions
</u>
The problem describes a function that expresses the concentration of an antibiotic in mg/dl vs time in hours as:
We need to find the first value of t such that
It means that
Operating with the inequality
Rearranging and dividing by 2, we have a polynomial inequality:
Factoring
There are two possible values for t, both valids because they are positive
We need to find the first value, i.e.
Now for the graphic method, we plot the graph for the function and a horizontal line at c=4 to find the values of t.
The graph is shown in the image provided below. We can see both values where the funcion and C=4 intersect. Both values coincide with the previously analitically found values
Answer:
Perpendicular
Step-by-step explanation:
