Maybe 88 not sure that is the givin
An ellipse (oval shape) is expressed by the following equation:

where h is the x coordinate of the center and k is the y coordinate of the center. Furthermore, a is the horizontal distance from the center, and b is the vertical distance from the center. Lastly, c is the distance from the center to one of the foci (they are spaced apart equally).
We can find the foci by using

36 - 11 =


Since the k value in this case is 0, the y value of both foci are 0. Also, since h and k are both 0, we know the center of the ellipse is at the origin.
So the foci are (-5, 0) and (5, 0)
Hope this helps :)
Roots: - √5 , √5, and - 3
=> these are factors of the polynomial: (x + √5), (x - √5), and (x + 3).
Multiply those three factors:
(x + √5) (x - √5) ( x + 3) = [x^2 - 5] ( x + 3 ) = x^2 + 3x^2 - 5x - 15
Therefore the polynomial x^2 + 3x^2 - 5x - 15 is a polynomial with the given roots.
Answer: option B. x^3 + 3x^2 - 5x - 15
A/c = 8.....a = 8c
a * c = 2 ...a = 2/c
a/b = -16 ...a = -16b
a * b = -1....
b/c = -0.5
2/c = 8c
2 = 8c^2
1/4 = c^2
sqrt 1/4 = c
0.5 (or 1/2) = c <===
a * c = 2
0.5a = 2
a = 2/0.5
a = 4 <===
a = -16b
4 = -16b
4/-16 = b
-1/4 (or - 0.25) = b <===
Answer: x=−3 or x=13
Step-by-step explanation:
Step 1: Subtract 39 from both sides.
x2−10x−39=39−39
x2−10x−39=0
Step 2: Factor left side of equation.
(x+3)(x−13)=0
Step 3: Set factors equal to 0.
x+3=0 or x−13=0
x=−3 or x=13