5x^7 , Y^11 is your answer
The perimeter of the figure to the nearest hundredth is 50.26 cm.
<h3>Perimeter of a figure.</h3>
The perimeter of a figure is the sum of the whole sides of the figure.
The perimeter of the figure can be found as follows:
perimeter of the figure = 12 + 5 + 5 + circumference of the semi circle
circumference of the semi circle = πr
where
perimeter of the figure = 22 + πr
perimeter of the figure = 22 + 3.14(9)
perimeter of the figure = 22 + 28.26
perimeter of the figure = 50.26 cm
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Answer:
-2/3
3/2
Step-by-step explanation:
So to have a line parallel the equation is: m1 = m2, meaning the slope (represented by m in this equation) is equal. So in the equation. 3y = - 2x + 4 you need to simplify the equation by dividing both sides by 3. Which would be like so: y = - 2/3x + 4/3, which the slope will be -2/3.
To be perpindicular you need the slope to be: m1 * m2 = - 1. So because we already know that the slope is -2/3, all we need to do is set up an equation: -2/3 * y = - 1
-2/3y = - 1
multiply both sides by 3/-2
y = 3/2
Answer:
2.5 bottles
Step-by-step explanation:
10 * 500 ml = 5000 ml
5000 ml = 5 l
5/2 = 2.5
6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks
<u>Step-by-step explanation:</u>
We have , Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet: 1.25 cups of dry food. Based on these averages . We need to find how many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks . We need to find how much they eat for 14 days as:
Trenton's pet: 4/5 cup of dry food•
With 4/5 per day , for 14 days :
⇒ 
⇒ 
⇒ 
Maria's pet: 1.25 cups of dry food.
With 1.25 per day , for 14 days :
⇒ 
⇒ 
Subtracting Maria's - Trenton's :
⇒ 
That means , 6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks