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solmaris [256]
2 years ago
6

Students who attend Anytown College pay either in-state or out-of-state tuition, depending on where they reside. The mean and st

andard deviation of the sum, S, of tuition for a randomly selected pair of in-state and out-of-state students are μS = $6,348.75 and σS = $1,508.48. How can these values be interpreted? Check all that apply. The average of the sums of both types of tuitions would be $6,348.75 for many, many randomly selected pairs of students. Students who pay both types of tuition will pay $6,348.75 per semester. For a pair of randomly selected in- and out-of-state students, the sum of their tuitions is $6,348.75. For a pair of randomly selected in- and out-of-state students, the sum of their tuitions typically varies from the mean of $6,348.75 by about $1,508.48. Students who pay both in- and out-of-state tuition should expect their cost to vary by about $1,508.48 per semester.
Mathematics
2 answers:
Oduvanchick [21]2 years ago
8 0

A.) The average of the sums of both types of tuitions would be $6,348.75 for many, many randomly selected pairs of students.

&

D.) For a pair of randomly selected in- and out-of-state students, the sum of their tuitions typically varies from the mean of $6,348.75 by about $1,508.48.

netineya [11]2 years ago
6 0

Answer:

For a pair of randomly selected in- and out-of-state students, the sum of their tuition typically varies from the mean of $6,348.75 by about $1,508.48.

Step-by-step explanation:

Given

\mu S = \$6,348.75

\sigma S = \$1,508

Required

Interpret the standard deviations

In statistic, standard deviation is a measure of how the given data lies away (or varies) from the mean.

This implies that:

For the in-state students, the standard deviation measures how the sum of their tuition varies from 6348.75

For the out-state students, the standard deviation measures how the sum of their tuition varies from 1508

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Disclaimer: This question was incomplete. Please find the full content below.

Question:

Suppose the p-value is 0.1038. What is the correct interpretation of this p-value in context?

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d.) There is a 0.1038 probability that the proportion of students who use drugs at this college is equal to 0.157.

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