Answer:
B) y = x + 2
Step-by-step explanation:
Coordinates of point C =
Coordinates of point D=
To find the equation of segment CD
Formula : 
Substitute the values in the formula :
y-12=x-6
y=x+6
When two lines are perpendicular to each other the product of their slopes is -1
Let the slope of perpendicular line be x
So, -1 \times x = -1
So, x =1
General equation : y = mx+c
So, Option B has slope = 1
So,the equation of the line that's a perpendicular bisector of the segment connecting C (6, –12) and D (10, –8) is y = x + 2
If it's 2 free throws in a row the there is a 1/5 probability. 2/5*2/5=1/5
In the triangle...the length of the longer side is tan 60 multiply by the shorter leg. Tan 60 = sq root 3...thus
Longer side = sq root 3 times the length of the shorter leg
Answer:
The range of crying times within 68% of the data is (5.9, 8.1).
The range of crying times within 95% of the data is (4.8, 9.2).
The range of crying times within 99.7% of the data is (3.7, 10.3).
Step-by-step explanation:
According to the Empirical Rule in a normal distribution with mean µ and standard deviation σ, nearly all the data will fall within 3 standard deviations of the mean. The empirical rule can be broken into three parts:
- 68% data falls within 1 standard deviation of the mean. That is P (µ - σ ≤ X ≤ µ + σ) = 0.68.
- 95% data falls within 2 standard deviations of the mean. That is P (µ - 2σ ≤ X ≤ µ + 2σ) = 0.95.
- 99.7% data falls within 3 standard deviations of the mean. That is P (µ - 3σ ≤ X ≤ µ + 3σ) = 0.997.
The mean and standard deviation are:
µ = 7
σ = 1.1
Compute the range of crying times within 68% of the data as follows:
The range of crying times within 68% of the data is (5.9, 8.1).
Compute the range of crying times within 95% of the data as follows:
The range of crying times within 95% of the data is (4.8, 9.2).
Compute the range of crying times within 99.7% of the data as follows:
The range of crying times within 99.7% of the data is (3.7, 10.3).
