Hello :
<span>3y = x + 6 ...(1)
y – x = 3...(2)
by (2) : y = x+3...(*)
subsct in (1) :
3(x+3) = x+6
3x-x= -9+6
2x= -3
x=-3/2
subsct in (*) : y =-3/2 +3 =3/2</span>
The angle between two vectors is given by:
cos (x) = (v1.v2) / (lv1l * lv2l)
We have then:
v1.v2 = (2, -5). (4, -3)
v1.v2 = (2 * 4) + (-5 * (- 3))
v1.v2 = 8 + 15
v1.v2 = 23
We look for the vector module:
lv1l = root ((2) ^ 2 + (-5) ^ 2)
lv1l = 5.385164807
lv2l = root ((4) ^ 2 + (-3) ^ 2)
lv2l = 5
Substituting values:
cos (x) = (23) / ((5.385164807) * (5))
x = acos ((23) / ((5.385164807) * (5)))
x = 31.33 degrees
Answer:
The angle between the two vectors is:
x = 31.33 degrees
Even numbers are numbers that can be divisible by 2, so in this case
28, 30, 32, 34, 36, 38
^ are even numbers because they can be divided by 2
