Define x:
Let angle a be x.
angle a = x
angle b = 3x + 32
angle c = x + 58
Find x:
Angles in a triangle add up to 180°:
x + 3x + 32 + x + 58 = 180
Combine like terms:
5x + 90 = 180
Take away 90 from both sides:
5x = 90
Divide by 5 on both sides:
x = 18°
Find the angles:
angle a = x = 18°
angle b = 3x + 32 = 3(18) + 32 = 86°
angle c = x + 58 = 18 + 58 = 76°
Answer: The angles are 18°, 86° and 76°.
So if the measure of angle AMB = 90 so the another right triangle is formed which is ADM, since the it is a right triangle the legs are equal, then the lenght AD = DM and we can solve the length of AM
AM = sqrt( AD^2 + DM^2)
AM = sqrt( 6^2 + 6^2)
AM = 6sqrt(2)
now we can solve the length of AB
AB = sqrt ( AM^2 + MB^2)
AB = sqrt ( 6sqrt(2)^2 + 6sqrt(2)^2)
AB = 12
so the perimeter = 2(6) + 2(12) = 36
Answer: I think the perimeter is 17ab4
Step-by-step explanation:
