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2 years ago

Find the value of x that makes the quadrilateral a parallelogram. 3x + 5 5x - 9 X =

Mathematics

2 answers:

oksano4ka [1.4K]2 years ago

5 0

Answer: x=7

Step-by-step explanation:

both the sides have to be equal.

3x+5=5x-9

2x=14

x=7

Lady bird [3.3K]2 years ago

4 0

Answer:

3x+5=5x-9(llgram oppositesides are equal)

3x-5x= -9-5

-2x=-14

x= -14/-2

x=7

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victus00 [196]

Answer:

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2 years ago

Each member of the swim team must pay $76 to join the team. There are 376 members. How much does the team receive in dues?

Basile [38]

Answer:

$28,576

Step-by-step explanation:

$76 (amount that each member pays) * 376 (total members) = $28,576 (amount that will be received in dues)

I hope this helps :)

7 0

3 years ago

The population of a particular city is given by the function P(t) = 27,400(1.07)t, where t is the time in years and P(t) is the

otez555 [7]

Answer:

27,400 is the current population

7% is the rate of increase

The new size is:

38,430 is the population if t is an exponent

146,590 is t is NOT an exponent in the formula you typed

Step-by-step explanation:

To find the population in a future year, use the formula:

$P(t) = 27,400(1.07)t$

Substitute the value t=5 to find the population in 5 years.

$P(t) = 27,400(1.07)t\\P(t) = 27,400(1.07)(5)\\P(t) = 146,590$

Or if the equation is supposed to have t as an exponent then look below:

$P(t) = 27,400(1.07)^t$

Substitute the value t=5 to find the population in 5 years.

$P(t) = 27,400(1.07)^t\\P(t) = 27,400(1.07)^(5)\\P(t) = 38,430$

This formula is based off the standard formula $A=A_0(1+r)^t$ so r, the rate is 1.07=1+0.07 so r is 7%.

$A_0$ is the starting population which is 27,400 here.

4 0

3 years ago

What is the equation process to this question?

Andreyy89

The given equation is $h(t)=-16t^2+80t+4$ where h is the height, in feet, of a ball and t is the time, in seconds.

<u>Part a: The height of the ball when t = 2 seconds:</u>

The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation $h(t)=-16t^2+80t+4$ , we get;

$h(2)=-16(2)^2+80(2)+4$

Simplifying the terms, we get;

$h(2)=-64+160+4$

$h(2)=100$

Thus, the height of the ball after 2 seconds is 100 feet.

<u>Part b: The height of the ball when t = 4 seconds:</u>

The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation $h(t)=-16t^2+80t+4$ , we get;

$h(4)=-16(4)^2+80(4)+4$