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lakkis [162]
4 years ago
9

How many neutrons does element x have if it’s atomic number is 31 and it’s mass number is 88?

Physics
1 answer:
tresset_1 [31]4 years ago
4 0
You would find the answer by doing 88-31 which is equal to 57. The answer is 57
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You drop a basketball (Mass = 0.5 kg) and a medicine ball (mass = 5 kg) from the window of the leaning tower of Pisa. Assuming t
erastova [34]
The medicine ball wall hit the ground faster, if that makes sense to you
4 0
3 years ago
A car undergoing uniform acceleration travels 100 meters from a standing start in a given period of time. If the time were incre
iogann1982 [59]

Answer:

d = 1600 m

Explanation:

If car start from rest and accelerates uniformly then the displacement of the car is given as

d = v_i t + \frac{1}{2}at^2

now we know

d = 0 + \frac{1}{2}at^2

now if the same car will accelerate from rest for four times of the previous time interval

then we will have

d = 0 + \frac{1}{2}a(4t)^2

d = 16(\frac{1}{2}at^2)

so the distance will be 16 times more

d = 1600 m

5 0
4 years ago
A proton and an electron are fixed in space with a separation of 859 nm. Calculate the electric potential at the midpoint betwee
makkiz [27]

Answer:

The electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts

Explanation:

Electric potential is given as;

V = E*r

where;

E is the electric field strength, = kq/r²

V = ( kq/r²)*r

V = kq/r

k is coulomb's constant = 8.99 X 10⁹ Nm²/C²

q is the charge of the particles = 1.6 X 10⁻¹⁹ C

r is the distance between the particles = 859 nm

At midpoint, the distance = r/2 = 859nm/2 = 429.5 nm

V = (8.99 X 10⁹  * 1.6 X 10⁻¹⁹)/ (429.5 X 10⁻⁹)

V = 3.349 X 10⁻³ Volts

Therefore, the electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts

3 0
3 years ago
In one experiment, the students allow the block to oscillate after stretching the spring a distance A. If the potential energy s
atroni [7]

Answer:

    K = m g (A - A2)

Explanation:

In a block spring system the total energy is the sum of the potential energy plus the kinetic energy, for maximum elongation all the energy is potential

         Em = U₀ = m g A

For when the system is at an ele

Elongation A2 less than A, energy has two parts

        Em = K + U₂

       K = Em –U₂

We substitute

     K = m g A - m gA2

    K = m g (A - A2)

3 0
4 years ago
Read 2 more answers
A jetliner is moving at a speed of 245m/s. The vertical component of the plane's velocity is 40.6 m/s. Determine the magnitude o
Harman [31]

Answer:

Horizontal component of velocity = 241.61 m/s

Explanation:

Given that,

Velocity of a jetliner is 245 m/s

The vertical component of the plane's velocity is 40.6 m/s, v_y=40.6\ m/s

We need to find the magnitude of the horizontal component of the plane velocity.

The resultant velocity is given by :

v=\sqrt{v_x^2+v_y^2}

Where, v_x is the horizontal component of the plane velocity

v^2=v_x^2+v_y^2\\\\v_x^2=v^2-v_y^2\\\\v_x^2=(245)^2-(40.6)^2\\\\v_x=\sqrt{58376.64}\\\\v_x=241.61\ m/s

So, the magnitude of the horizontal component of the plane velocity is 241.61 m/s.

8 0
3 years ago
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