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xeze [42]
3 years ago
8

Using the interactive map, available at ejatlas.org, identify two separate environmental justice issues ongoing anywhere in the

world. The issues must be connected in someway, which you should justify. For these issues, you must make mention of:
What is the specific issue?

Who are the people causing the environmental problem, and who are demanding environmental justice?

What are the demands environmental justice protestors are making, and is it possible for these to be reconciled with existing practices?
Physics
1 answer:
NeTakaya3 years ago
8 0

Answer:

Explanation:

1) The specific issue is the emission of the CO2 gases into the atmosphere and conflicts over coal extraction as leaving the oil in the soil.

2)Land acquisition conflicts and the Agro fuels industries and biomass energy plants are causing more environmental problems.

EJOCT project is meant for considering the causes of climate debt and ecological debt and designed many projects under the clean development mechanism allowing rich countries to offset their emissions by reducing emissions.

Large parts of the global justice movement united around a push for the concept of climate debt in copenhagen climate summit.In the people's summit in Bolivia in 2010, climate debt was considered as the over consumption of the Earth's atmosphere and climate system to absorb green house gases by the developed countries. The map shows the spatial mal distribution of climate change sources and its impacts.

Yes the methods the Summits are taking are correct and can reduce the emission of CO2 gases. The methods they were implementing are supportable to the environment.If the people follow those methods the climate debt can be minimised.I have taken this topic as the emission of CO2 gases is the main problem all the world.Due to this the melting of Ice and Global warming are occuring.This was the main problem to solve all over the world as the no. of Industries and vehicles and population is increasing.These movements are an appropriate way to change and improve the environment in which people have to live.

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3. An object with a mass of 10 kg is moving along a horizontal surface. At a certain point it has 40 J of kinetic energy. If the
damaskus [11]

Answer: 100cm

Explanation:

The force of friction on a surface normal to gravity where µ is the coefficient of friction is

F = µmg

Where

F = the friction force

µ = coefficient of friction

m = mass of the object

g = acceleration due to gravity

Also, the Kinetic Energy of the object, E = Fs, where

E = Kinetic Energy

s = stopping distance. So that,

E = µmgs

40 J = 0.4 * 10 kg * 10 m/s² * s

40 J = 40 kgm/s² * s

s = 40 J / 40 kgm/s²

s = 1 m or 100 cm

7 0
3 years ago
Which of the following equations describes Newton’s second law
svp [43]
C.

Newton’s Second Law is F=ma (force is equal to the mass multiplied by acceleration), however, the equation can be rearranged to isolate and calculate mass from force over acceleration. Therefore, m=F/a
8 0
3 years ago
Read 2 more answers
large truck exerts 7000 n of force on a piston with an area of 0.4m squared and the is ton can only support 16,000 pa of pressur
sasho [114]
7000 N / 0,4m^2  = 17 500 Pa.
6 0
3 years ago
Question 4. A tuning fork ‘A’ produces 6 beats/sec with another fork ‘B’ of un-known frequency. On
8090 [49]

Clever problem.

We know that the beat frequency is the DIFFERENCE between the frequencies of the two tuning forks.  So if Fork-A is 256 Hz and the beat is      6 Hz, then Fork-B has to be EITHER 250 Hz OR 262 Hz.  But which one is it ?

Well, loading Fork-B with wax increases its mass and makes it vibrate SLOWER, and when that happens, the beat drops to 5 Hz.  That means that when Fork-B slowed down, its frequency got CLOSER to the frequency of Fork-A ... their DIFFERENCE dropped from 6 Hz to 5 Hz.

If slowing down Fork-B pushed it CLOSER to the frequency of Fork-A, then its natural frequency must be ABOVE Fork-A.

The natural frequency of Fork-B, after it gets cleaned up and returns to its normal condition, is 262 Hz.  While it was loaded with wax, it was 261 Hz.

4 0
3 years ago
A spring is stretched from x=0 to x=d, where x=0 is the equilibrium position of the spring. It is then compressed from x=0 to x=
VARVARA [1.3K]

Answer:

The same amount of energy is required to either stretch or compress the spring.

Explanation:

The amount of energy required to stretch or compress a spring is equal to the elastic potential energy stored by the spring:

U=\frac{1}{2}k (\Delta x)^2

where

k is the spring constant

\Delta x is the stretch/compression of the spring

In the first case, the spring is stretched from x=0 to x=d, so

\Delta x = d-0=d

and the amount of energy required is

U=\frac{1}{2}k d^2

In the second case, the spring is compressed from x=0 to x=-d, so

\Delta x = -d -0 = -d

and the amount of energy required is

U=\frac{1}{2}k (-d)^2= \frac{1}{2}kd^2

so we see that the amount of energy required is the same.

7 0
3 years ago
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