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il63 [147K]
3 years ago
12

The slow coning pattern of the spin axis of the Earth's precession will move the end of this axis in a complete circle in a peri

od of_________.
Physics
1 answer:
GREYUIT [131]3 years ago
3 0

Answer:

26000 years

Explanation:

Precession describes the angular motion of the Earth's body. Since the attitude of telescopes relative to the Earth's body can be controlled with high accuracy, and telescopes can measure the direction of incoming light also with high accuracy, the motion of Earth is under permanent high precision monitoring. Thus the basic numerical descriptor of precission, an angular rate of 5029.0966 seconds of arc per Julian century, traditionally denoted p (for precession) is a measured value from observed coordinate changes of thousands of stars over, say, two centuries. The understanding of this value in terms of forces acting on an oblate Earth from the Moon is well understood so that an extrapolation back and forth over a few full cycles contains little uncertainties. Of course, you can find details on the coordinate transformations mentioned above (the direct observational effect of precession) on the net. I was surprised to see that the Wikipedia article on precession covers the astronomical aspect very poorly. You thus better look for other sources.

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The binding energy of a nucleus is the energy equivalent of the mass discrepancy.
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ANSWER IS NOT FALSE IT IS True

6 0
3 years ago
Frost wedging happens when _____.
KiRa [710]

Answer: water freezes inside a rock, causing it to break

Weathering is a natural process in which the rocks break into pieces or sediments by the action of wind, water and chemical agents. Frost wedging is a physical weathering process. It occurs in an area where temperature fluctuations occurs due to change in the climatic conditions. This occurs due to rapid heating and cooling. The rocks lying in a cold environment, the water residing in the rocks gets freezed. The water in ice form that is solid form acquire more space than in liquid form, therefore, the developed ice will affect the physical structure of the rock. The formation of ice results in the development of break or crack in the rock typically in the shape of a wedge and thus the phenomena is called as frost wedging.

Hence, frost wedging happens when water freezes inside a rock, causing it to break.

8 0
3 years ago
If Tony and Tanya both run at the same speed and in the same direction and they both run for the same amount of time, what can y
Marina86 [1]

Answer: They travel equal distances

Explanation:

Distance is amount of space covered from one point to another. It is measured in metres. Distance = speed x time taken

In this case,

- Since Tony and Tanya both run at the same speed: let speed = b

- Also, both run for the same amount of time: let time = c

Therefore, distance covered by Tony and Tanya = speed x time taken

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8 0
3 years ago
A cylindrical tank of methanol has a mass of 70 kg and a volume of 75 L. Determine the methanol’s weight, density, and specific
dem82 [27]

Answer:

Weight=686.7N, \rho=933kg/m^{3}, S.G.=0.933, F=17.5N

Explanation:

So, the first value the problem is asking us for is the weight of methanol. (This is supposing there is a mass of methanol of 70kg inside the tank). We can find this by using the formula:

W=mg

so we can substitute the data the problem provided us with to get:

W=70kg(9.81m/s^{2})

which yields:

W=686.7N

Next, we need to find the density of methanol, which can be found by using the following formula:

\rho=\frac{m}{V}

we know the volume of methanol is 75L, so we can convert that to m^{3} like this:

75L*\frac{0.001m^{3}}{1L}=0.075m^{3}

so we can now use the density formula to find our the methanol's density, so we get:

\rho=\frac{m}{V}

\rho=\frac{70kg}{0.075m^{3}}

\rho=933.33kg/m^{3}

Next, we can us these values to find the specific gravity of methanol by using the formula:

S.G.=\frac{\rho_{sample}}{\rho_{H_{2}O}}

when substituting the known values we get:

S.G.=\frac{933.33kg/m^{3}}{1000kg/m^{3}}

so:

S.G.=0.933

We can now find the force it takes to accelerate this tank linearly at 0.25m/s^{2}

F=ma

F=(70kg)(0.25m/s^{2})

F=17.5N

6 0
3 years ago
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