Answer: 
Step-by-step explanation:
Given
Two forces of 9 and 13 lbs acts
angle to each other
The resultant of the two forces is given by

Insert the values

Resultant makes an angle of

So, the resultant makes an angle of
with 9 lb force
Angle made with 13 lb force is 
I believe it is 180° around H and translate 2 up 5 right
75% is equal to 3/4. So the easiest way to do this is to make the smaller number a multiple of 4. Let's say the smaller number is 8. To find the larger number, you must take 75% of 8 and then add it to 8. 1/4 of 8 equals 8 divided by 4, which is 2. Therefore, 3/4 of 8 is 6. 8 + 6 = 14.
Thus, your two numbers could be 8 and 14.
-(3/4) (12)+1 = -9+1=. -8
Answers: height, "h", of a triangle: <span> h = 2A / (b₁ + b₂) .
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Explanation:
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The area of a triangle, "A", is equal to (1/2) * (b₁ + b₂) * h ;
or: A = (1/2) * (b₁ + b₂) * h
or: write as: A = [(b₁ + b₂) * h] / 2 ;
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in which: A = area of the triangle;
b₁ = length of one of the bases
of the triangle ("base 1");
b₂ = length of the other base
of the triangle ("base 2");
h = height of the triangle;
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To find the height of the triangle, we rearrange the formula to solve for "h" (height); assuming that all the units are the same (e.g. feet, centimeters); if no "units" are given, then the assumption is that the units are all the same.
We can use the term "units" if desired, in such cases; in which the area, "A" is measured in "square units"; or "units²",
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So, given our formula for the "Area, "A"; of a triangle:
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A = [(b₁ + b₂) * h] / 2 ; we solve for "h" in terms of the other values; by isolating "h" (height) on one side of the equation.
If we knew the other values; we plug in the those other values.
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Given: A = [(b₁ + b₂) * h] / 2 ;
Multiply EACH side of the equation by "2" ;
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2*A = { [(b₁ + b₂) * h] / 2 } * 2 ;
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to get:
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2A = (b₁ + b₂) * h ;
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Now, divide EACH side of the equation by: "(b₁ + b₂)" ; to isolate "h"
on one side of the equation; and solve for "h" (height) in terms of the other values;
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2A / (b₁ + b₂) = [ (b₁ + b₂) * h ] / (b₁ + b₂);
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to get:
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2A / (b₁ + b₂) = h ; ↔<span> h = 2A / (b₁ + b₂) .
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