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3 years ago

Need help how can i do this?

Mathematics

2 answers:

Lunna [17]3 years ago

8 0

<u>Answer:</u>

E = 33

<u>Step-by-step explanation:</u>

We are given the number of faces and vertices and we are to find the number of edges.

We know the formula that relates the number of faces, number of vertices and the number of edges:

F + V - E = 2

Substituting the given values to find E (number of edges):

24 + 11 - E = 2

35 - 2 = E

E = 33

TEA [102]3 years ago

7 0

ANSWER

$\boxed {c. \: \: 33}$

EXPLANATION

The relationship between the number of faces, number of vertices and number of edges of a solid shape is given by the formula,

$F+V-2=E$

It was given that, F=24 and V=11.

We substitute these values into the formula to obtain,

$24+11-2=E$

We solve for E to get,

$33=E$

or

$E = 33$

Therefore the correct answer is C

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The formula for the volume of a sphere is v= 4/3 m^3 what is the formula solved for r ?

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Answer:

r = ∛ ( ---------- )

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Step-by-step explanation:

Please, enclose the fraction 4/3 inside parentheses, to eliminate any possibility of misreading this fraction. Also note that this formula MUST include "pi," symbolized by π.

V = (4/3) π r³ This formula does NOT include "m," which is a unit of measurement, not a variable.

Our task is to solve this formula for the radius, r.

Divide both sides by (4/3) π, to isolate r³. This results in:

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3 years ago

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Answer:

She lands on 92.

Step-by-step explanation:

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3 years ago

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malfutka [58]

Answer:

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2 years ago

Read 2 more answers

Factor completely x^8- 16.

Nataly_w [17]

Answer:

Step-by-step explanation:

So in this example we'll be using the difference of squares which essentially states that: $(a-b)(a+b)=a^2-b^2$ or another way to think of it would be: $a-b=(\sqrt{a}-\sqrt{b})(\sqrt{a}+\sqrt{b})$ . So in this example you'll notice both terms are perfect squares. in fact x^n is a perfect square as long as n is even. This is because if it's even it can be split into two groups evenly for example, in this case we have x^8. so the square root is x^4 because you can split this up into (x * x * x * x) * (x * x * x * x) = x^8. Two groups with equal value multiplying to get x^8, that's what the square root is. So using these we can rewrite the equation as:

$x^8-16 = (x^4-4)(x^4+4)$

Now in this case you'll notice the degree is still even (it's 4) and the 4 is also a perfect square, and it's a difference of squares in one of the factors, so it can further be rewritten:

$x^4-4 = (x^2-2)(x^2+2)$

So completely factored form is: $(x^2-2)(x^2+4)(x^4+4)$

I'm assuming that's considered completely factored but you can technically factor it further. While the identity difference of squares technically only applies to difference of squares, it can also be used on the sum of squares, but you need to use imaginary numbers. Because $x^2+4 = x^2-(-4)$ . and in this case a=x^2 and b=-4. So rewriting it as the difference of squares becomes: $x^4+4 = x^4 - (-4) = (x^2-\sqrt{-4})(x^2+\sqrt{-4}) = (x^2-2i)(x^2+2i)$ just something that might be useful in some cases.